Answer:
a. keeps its speed for a short while, then slows and stops. slows steadily until it stops.
Explanation:
Since the tension in the rope, t is greater than the kinetic friction fk, the box is moving forward because there is a net force on it. That is, t - fk = f = ma.
Since there is a net force, there is an acceleration and thus an increasing velocity.
When the rope breaks, the tension, t = 0. So, t - fk = 0 - fk = -fk = ma'.
Now, the net force acting on the box is friction in the opposite direction. This force tends to slow the box down from its initial velocity at acceleration, 'a' until its velocity is zero, where it stops. Since the frictional force is constant, the acceleration, a' on the box is thus constant and the box undergoes uniform deceleration until its velocity is zero.
<u>So, the box keeps its speed for a short while, then slows and stops. slows steadily until it stops.</u>
So, the answer is a.
The reason is that a closed system has nothing going in or out and water retains energy very well also water it polar so it is attracted to itself. It doesnt like contact with other things.
So it's likely to be C
Answer:
0.0078 N
Explanation:
The electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
The force is attractive if the two charges have opposite sign, and repulsive if the two charges have same sign.
In this problem, we have:
located at 
located at 
located at 
The force between charge 1 and charge 2 is:

And since the two charges have opposite sign, the force is attractive, so the force on charge 1 is towards the right.
The force between charge 1 and charge 3 is:

And since the two charges have same sign, the force is repulsive, so the force on charge 1 is towards the left.
Therefore, the net force on charge 1 is:

towards the right.
Answer
a) charge of the sodium ion is,
q = n e
q = 2.68 x 10¹⁶ x 1.6 x 10⁻¹⁹
q = 4.288 x 10⁻³ C
charge of the chlorine ion is,
q' = n e
q' = 3.92 x 10¹⁶ x 1.6 x 10⁻¹⁹
q' = 6.272 x 10⁻³ C
the current



b) positive ion moves toward negative electrode hence direction of will be in the direction toward negative electrode.