Question

Pat Kinch used a racing cycle to travel 75.57 km/h. Suppose Kinch moved at this speed around a circular track. If the combined mass of Kinch and the cycle was 92.0 kg and the average centripetal force was 12.8 N, what was the radius of the track? What is the unit of the radius?

Answer 1

Answer:

Radius of the track is 3376.40 n

Explanation:

We have given speed v = 75.75 km/hr = $75.57\times \frac{5}{18}=21m/sec$

Mass is  given m = 92 kg  

Centripetal force is given F = 12.8 N

We have to find the radius of the curve

Centripetal force is equal to $F=\frac{mv^2}{r}$

So $12.8=\frac{92\times 21^2}{r}$

r = 3376.40 m

So radius of the circular track is 3376.40 m as the SI unit is m so it will be 3376.40 m