270 degrees or -90 degrees.
The question is incomplete, as the depth of the hook isn't given in the question. However, using a proposed depth for the hook, we could give a stepwise solution to the exercise.
Answer:
Kindly check explanation
Step-by-step explanation:
If given a hook depth of 6 meters, and a distance of 8 m(fishing line from hook) at the the Same depth, then the distance between rose and the fish, x can be calculated, using the relation.
Hypotenus² = opposite² + adjacent²
(refer to attached picture)
x² = 6² + 8²
x² = 36 +. 64
x² = 100
x = sqrt(100)
x = 10 meters
You can use the actual depth value to obtain the actual solution to your question.
So find g(0) and g(3)
G(0) = 0^2 -5(0) +3 = 3
And g(3) = 3^2 - 5(3) +3 = 9 - 15 + 3 = 3 so there is no change in g(x) for that interval.
H(0) = 8(0) + 10 = 10
And h(3) = 8(3) + 10 = 34
So the change in h(x) for that interval is 24.
Area of a circle is pi x r ^2
R = diameter/2
R = 1.8/2 = 0.9
Area = 3.142 x 0.9^2
Area = 2.5 square cm.