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inessss [21]
3 years ago
5

What is the difference between 213 and 312

Mathematics
2 answers:
ra1l [238]3 years ago
8 0

Answer:

99

Step-by-step explanation:

312 - 213 = 99

NeTakaya3 years ago
6 0

Answer:

-99

Step-by-step explanation:

because if you do 213 then subtract it by 312 you would get -99

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Do you know what is 1/5 of 35
deff fn [24]

Answer:

7

Step-by-step explanation:

Because 35/5=7 so 1/5 of 35 would = 7

7 0
4 years ago
Read 2 more answers
What is the coefficient of y in the expression 2x4+3y
coldgirl [10]

Answer:

3

Step-by-step explanation:

5 0
3 years ago
Solve for x: 4(x-2)+6=2(5x-6)
Katarina [22]

4(x - 2) + 6 = 2(5x - 6)     <em>use distributive property</em>

(4)(x) + (4)(-2) + 6 = (2)(5x) + (2)(-6)

4x - 8 + 6 = 10x - 12

4x - 2 = 10x - 12       <em>add 2 to both sides</em>

4x = 10x - 10       <em>subtract 10 from both sides</em>

-6x = -10      <em>divide both sides by (-6)</em>

x = 10/6

<h3>x = 5/3</h3>
8 0
3 years ago
If a polynomial function f(x) has roots –8, 1, and 6i, what must also be a root of f(x)? A. –6
anyanavicka [17]

Answer:

-6i

Step-by-step explanation:

Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.

If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.

x + 8 = 0

x = -8

x - 1 = 0

x = 1

x^2 + 36 = 0

x^2 = -36 ... take the square root of both sides to get x alone

x = √-36 ... square root of an imaginary number produces the usual square root and an "i"

x = ±6i

6 0
3 years ago
Read 2 more answers
Given: &lt;PQR is a right angle Prove: &lt;PQS and &lt;SQR are complemantary​
amm1812

Answer:

see the explanation

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠PQS+m∠SQR=m∠PQR ----> equation A (by Addition Angle Postulate)

we have that

m∠PQR=90° ----> equation B given problem (because is a right angle)

substitute equation B in equation A

m∠PQS+m∠SQR=90°

Remember that

Two angles re complementary is their sum is equal to 90 degrees (Definition of complementary angles)

therefore

m∠PQS and m∠SQR are complementary angles

3 0
3 years ago
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