1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
beks73 [17]
3 years ago
7

Which sequence of transformations on △ABC will result in a figure that is congruent to △ABC?

Mathematics
2 answers:
ryzh [129]3 years ago
6 0
Any sequence of transformations that include a “dilation” changes the overall size of the shape, so your answer would actually be “B” since it’s only being rotated and reflected. In other words, the location of the shape is the only thing being changed.
solong [7]3 years ago
3 0

Answer: A.) c is -1 -2 b is -4 -2 a is -3 -3

Step-by-step explanation: sry but thats all i know i hoped i helped a lil bit :)

You might be interested in
Please tell me the area and attach work the most important part is work since I’m confused on subtracting the side lengths
Ymorist [56]

Answer:

The area is 288 feet

Step-by-step explanation:

So the best way to solve problems like this is to think about the parts of the object like different things, and iscolating them.

We see that the length of the rectangle is 21, and the width is 13.

Ignore the 5 and 16, since they tell you what you neeed to know about the other smaller rectangle.

So lets just use the formula for area of a rectnagle, which is l*w, using the 21 and 13 values above:

21*13= 273

Now lets look at the second part.

I think this is the part you were confused with, so I will go into detail on how we find the area of this part of the rectangle

We see that there is a 16...However, we already know that the width is 13. So how is this? The 16 includes both the width of the rectangle and of the smaller piece.

Since we already know that the width of the rectangle is 13, but the small segment makes it 16, we can subtract the total wifth by the width of the rectangle, which will find us the width of the segment:

16-13=3

So the width is 3.

This is not what we do with the 21 and 5. When we look at the segment, we see that the 5 covers all of it, and does not cover any of the rectangle's length. This basicallly means that the 5 length is only for the segment, so this is considered our length.

Now we can use this to figure out the segments area:

3*5=15

Now, since we need to find the combined area of the both the segment and the rectangle, we need to add them together:

273+15=288

So the area is 288 in total.

Hope this helps!

7 0
3 years ago
What is the surface area of a cylindrical ring where the diameter of the cross section is 6.3 in and the center line has a lengt
Kruka [31]
The surface area of the cylindrical ring is given by
πdh
where d is the diameter and h is the height:
π•6.3•48 = 950.02
The answer is C. 950.02 in^2
4 0
3 years ago
Read 2 more answers
A pool measuring 8 meters by 28 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the poo
Greeley [361]
28 because the wiishddbehehhe is wide enough
3 0
3 years ago
Help help!!!!!!!!!!!!!!!!!!!!!!!
Paladinen [302]

Answer:

bottom right

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
Other questions:
  • A puppy and a kitten are 180 meters apart when they see each other. The puppy can run at a speed of 25 m/sec, while the kitten c
    7·1 answer
  • Find the altitude of the triangle
    13·1 answer
  • Triangle ABC has vertices of A(–6, 7), B(4, –1), and C(–2, –9). Find the length of the median from A) 4<br> b) square Root of 18
    14·1 answer
  • 306 is 51% of what number?
    12·2 answers
  • Find f(x) of -n^2 -3n if x is -5​
    5·1 answer
  • I need number 22 answered
    8·1 answer
  • a piece of fabric for a quilt design is in the shape of a parallelogram. the bas is 5 inches and the height is 3.5 inches. what
    6·2 answers
  • Rewrite the equation 2x + 6y = 7 in slope-intercept form.
    10·2 answers
  • 7th grade math help me pleasee
    6·1 answer
  • Pls can anybody give me the code to join khan academy online classes​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!