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vaieri [72.5K]
4 years ago
9

How is heat energy transferred from a warm object to a cold object there is direct contact?

Physics
2 answers:
sdas [7]4 years ago
8 0
A is the answer!!!!!!!!!!!!
eduard4 years ago
4 0

<u>Answer:</u> The heat is getting transferred by conduction.

<u>Explanation:</u>

There are 3 modes of heat transfer:

  • <u>Conduction:</u> This type of heat transfer happens when there is direct contact between the two objects.
  • <u>Convection:</u> This type of heat transfer happens when there is a movement of fluid (liquid or gas).
  • <u>Radiation:</u> This type of heat transfer happens when there is direct transfer of energy through space.

We are given:

Heat energy is getting transferred from a warm object to cold object by direct contact.

Hence, the heat is getting transferred by conduction.

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A hockey puck slides off the edge of a horizontal platform with an initial velocity of 28.0 m/shorizontally in a city where the
kozerog [31]

Answer:

θ = 12.60°

Explanation:

In order to calculate the angle below the horizontal for the velocity of the hockey puck, you need to calculate both x and y component of the velocity of the puck, and also you need to use the following formula:

\theta=tan^{-1}(\frac{v_y}{v_x})       (1)

θ: angle below he horizontal

vy: y component of the velocity just after the puck hits the ground

vx: x component of the velocity

The x component of the velocity is constant in the complete trajectory and is calculated by using the following formula:

v_x=v_o

vo: initial velocity = 28.0 m/s

The y component is calculated with the following equation:

v_y^2=v_{oy}^2+2gy         (2)

voy: vertical component of the initial velocity = 0m/s

g: gravitational acceleration = 9.8 m/s^2

y: height

You solve the equation (2) for vy and replace the values of the parameters:

v_y=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(2.00m)}=6.26\frac{m}{s}

Finally, you use the equation (1) to find the angle:

\theta=tan^{-1}(\frac{6.26m/s}{28.0m/s})=12.60\°

The angle below the horizontal is 12.60°

7 0
3 years ago
A pulley system has an efficiency of 74.2%. If you perform 200 J of work, how much useful work does the pulley perform?
kirill115 [55]

<span>Efficiency is the measure of how efficient a process is. It is used to assess the ability of a process in avoiding waste energy, materials, money and time in doing a desirable output. It is calculated as;

Efficiency = useful energy ouput / total energy input</span>

<span>
.742 = useful energy / 200 J
Useful energy = 148.4 J  <-----------OPTION B</span>
7 0
3 years ago
fossil fuels are formed by the decomposition of dead plants and animals. which flow chart describes the correct energy transform
umka2103 [35]
Chemical to kinetic +( heat + sound)

The energy formations in brackets are wasted and passed on to their surroundings.

Hope this helps! :)
8 0
3 years ago
What is the difference between a line that has a slope versus a line that is flat in a position vs. time graph?
MaRussiya [10]

Answer:

a slope means that object is accelerating

and a line means its moving at a constant speed

Explanation:

8 0
3 years ago
A magnet is pushed into a solenoid of 20 coils with a cross-sectional area of 4.0x10-4 m2. As a result, the magnetic field insid
kobusy [5.1K]

Given:

The number of the coils, N=20

The cross-sectional area of the solenoid, A=4.0×10⁻⁴ m²

The magnetic fields, B₁=0.0500 T

and B₂=0.180 T

The time interval, t=1.90 s

The resistance of the resistor, R=1.90 s

To find:

1. The magnitude of the induced emf.

2. The current flowing through the resistor.

Explanation:

1.

The magnitude of the induced emf in the solenoid is given by,

E=NA\frac{(B_2-B_1)}{t}

On substituting the known values,

\begin{gathered} E=20\times4.0\times10^{-4}\times\frac{(0.180-0.0500)}{1.90} \\ =0.55\times10^{-3}\text{ V} \\ =0.55\text{ mV} \end{gathered}

2.

From Ohm's law, The induced emf is given by,

E=IR

On substituting the known values,

\begin{gathered} 0.55\times10^{-3}=I\times5 \\ \Rightarrow I=\frac{0.55\times10^{-3}}{5} \\ =0.11\times10^{-3}\text{ A} \\ =0.11\text{ mA} \end{gathered}

Final answer:

1. The induced emf is 0.55 mV

2. The current through the given resistor is 0.11 mA

4 0
2 years ago
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