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Ymorist [56]
3 years ago
5

Which research method uses questionnaires to collect information about the participants in a study?

Physics
2 answers:
andrezito [222]3 years ago
8 0

Answer: survey research method.

Explanation: The survey research method studies the samples of individual units. It is a good way of collecting data from the participants of a study by using questionnaries. Surveys are useful to gather results that will be important in the future study.

musickatia [10]3 years ago
7 0
Survey research method uses questionnaires to collect information about the participants in a study.It is commonly used method of collecting information about a population of interest.
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According to Archimedes’ principle, the mass of a floating object equals the mass of the fluid displaced by the object. Use this
Andrew [12]

Answer:

Part a)

\rho = 0.55 g/cm^3

Part b)

\rho_L = 1.49 g/cm^3

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

Explanation:

Part a)

As we know that when cylinder float in the water then weight of the cylinder is counter balanced by the buoyancy force

So here we know

buoyancy force is given as

F_b = \rho_w V_{sub} g

F_b = (1 g/cm^3) (30 - 13.5) Ag

F_b = 16.5 Ag

Now we know that the weight of the cylinder is given as

W = \rho (30 cm)A g

now we have

\rho (30 cm) A g = 16.5 A g

\rho = 0.55 g/cm^3

Part b)

When the same cylinder is floating in other liquid then we will have

F_b = \rho_L (30 - 18.9 )A g

so we have

\rho_L (11.1) Ag = 0.55(30) Ag

\rho_L = 1.49 g/cm^3

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

3 0
3 years ago
A mass of 0.3 kg hangs motionless from a vertical spring whose length is 0.77 m and whose unstretched length is 0.59 m. Next the
vivado [14]

Answer:

Maximum spring length = 0.94m

Explanation:

Newton's law of forces in the vertical direction is given as:

Ef = Ks S - mg = 0

Ks = mg/ s

Ks = mg/ (L1 -Lo)

Ks =( 0.3 × 9.8 ) / ( 0.77 - 0.59 )

Ks = 2.94 / 0.18

Ks = 16.33N/m

The initial state is one in which the mass is pulled down so that the length of spring is 0.84m and the mass has initial speed of 1.8m/s. The final state is that in which the minimum point reached and the maximum length attained is L3

Ei = Ef

1/2mVi^2 + 1/2 Ks(L2-Lo)^2 + mg(L3- L2) = 1/2Ks(L3 - Lo)^2.

1/2 Mvi + 1/2 Ks(L2 - Lo)^2 + mg(L3 - L2)^2 = 1/2Ks(L3^2 - 2LoL3 + Lo^2)

1/2 KsL3 - (mg + KsLo)L3 + [1/2KsLo^2 + mgL2 - 1/2Ks(L2 -Lo)^2- 1/2mVi^2] = 0

Substituting the values to solve for L3 using the quadratic formula

1/2(16.33)L3^2 - (0.3×9.8) + 16.33(0.59)L3 + 1/2(16.33×0.59^2) + (0.3×9.8×0.84)- 1/2(16.33(0.84-0.59)^3 - 1/2( 0.3× 1.8^2] = 0

8.165L3^2 - 2.94 + 9.63L3 + 2.84 + 2.47 - 0.51 - 0.486

8.165L3^2 + 9.63L3 + 1.37

L3 =[ 9.63 +- sqrt(9.63^2 - 4(8.165)(1.37) / (2× 8.165)]

L3 =[ 9.63 +- sqrt(92.74 - 44.74) /16.33]

L3 = 9.63 +- sqrt(47.996)/16.43

L3 = 9.63 +- 6.93/ 16.33

L3 = (9.63 - 6.93)/16.34

L3 = 2.7/16.33

L3 = 0.165 + 0.77

L3= 0.935m

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Temperature decreases and the atmosphere gets thiner.

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.100(\:\rms)))$=2m/s (4)
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