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maxonik [38]
3 years ago
15

• What value is used to identify each element in the periodic table?​

Physics
1 answer:
bearhunter [10]3 years ago
5 0

Answer:

protons

Explanation:

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Air enters a turbine operating at steady state at 8 bar, 1400 K and expands to 0.8 bar. The turbine is well insulated, and kinet
vladimir2022 [97]

To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables

Mathematically this can be determined as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

Where

T_1 =Temperature at inlet of turbine

T_2 = Temperature at exit of turbine

P_1 = Pressure at exit of turbine

P_2 =Pressure at exit of turbine

The steady flow Energy equation for an open system is given as follows:

m_i = m_0 = m

m(h_i+\frac{V_i^2}{2}+gZ_i)+Q = m(h_0+\frac{V_0^2}{2}+gZ_0)+W

Where,

m = mass

m_i = mass at inlet

m_0= Mass at outlet

h_i = Enthalpy at inlet

h_0 = Enthalpy at outlet

W = Work done

Q = Heat transferred

V_i = Velocity at inlet

V_0= Velocity at outlet

Z_i= Height at inlet

Z_0= Height at outlet

For the insulated system with neglecting kinetic and potential energy effects

h_i = h_0 + W

W = h_i -h_0

Using the relation T-P we can find the final temperature:

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

\frac{T_2}{1400K} = (\frac{0.8bar}{8nar})^{(\frac{1.4-1}{1.4})}

T_2 = 725.126K

From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK

So:

W = h_i -h_0

W = C_p (T_1-T_2)

W = 1.005(1400-725.126)

W = 678.248kJ/Kg

Therefore the maximum theoretical work that could be developed by the turbine is 678.248kJ/kg

5 0
4 years ago
Researchers at the University of Georgia have evaluated trends in streamside forests in areas within roughly 400 feet of the sta
Colt1911 [192]
<span>B: adds aesthetic value to the landscape. Think about it, out of all your options, that's the one that doesn't really help anything.

And I took the test, so take my word for it.</span>
6 0
3 years ago
10 POINTS will mark brainliest if correct
PolarNik [594]
After putting stuff through google and some calculators, I’d say the answer is C.
6 0
4 years ago
A wave has angular velocity 12 rad/sec and maximum displacement X cm (X= last two digit [1] of your student’s ID). Calculate the
Naily [24]

Answer:

a=1440\ m/s^2

Explanation:

Given that,

The angular velocity of a wave, \omega=12\ rad/s

The maximum displacement of the wave, A = 10 cm (let)

The maximum acceleration of the wave is given by :

a=-A\omega^2

Put all the values,

a=10\times 12^2\\\\a=1440\ m/s^2

So, the maximum acceleration of the wave is equal to 1440\ m/s^2.

4 0
3 years ago
What is the average velocity of a car address for my .7 m to 2 m away from the garage in 3 seconds
stepan [7]

Answer:

v=\frac{5}{3}

Explanation:

So average velocity is calculated as

average velocity=\frac{total displacement}{total time}

Hence in our given case total displacement would be 5 m as the car moves a distance 7m to 2m.

Time taken for this moment is given to be 3 seconds.

Hence substituting back we get the average velocity as

v=\frac{5}{3}

Hence this is the average velocity in this case.

5 0
3 years ago
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