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2 years ago

15

• What value is used to identify each element in the periodic table?

1 answer:

bearhunter [10]2 years ago

5 0

Answer:

protons

Explanation:

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What type of nuclear radiation is emitted when carbon-14 decays

dalvyx [7]

Answer:

Beta radiation

Explanation:

Beta radiation is a radioactive phenomenon of nuclear decay in which an unstable atom or isotop, by transforming a neutron into a proton, or by transforming a proton into a neutron, becomes stable. For example, the decay of carbon 14 produces beta radiation.

6 0

3 years ago

To maintain a constant speed, the force provided by a car's engine must equal the drag force plus the force of friction of the r

sweet [91]

Answer:

a). 53.75 N and 101.92 N

b). 381.44 N and 723.25 N

Explanation:

$V= 77 \frac{km}{h}* \frac{1h}{3600 s} *\frac{1000m}{1 km} = 21.38 \frac{m}{s} \\V=106 \frac{km}{h}* \frac{1h}{3600 s} *\frac{1000m}{1 km} = 29.44 \frac{m}{s}$

a).

ρ $= 1.2 \frac{kg}{m^{3} }$ , $A_{t}= 0.7 m^{2}$ , $D_{t}= 0.28$

$F_{t1} = \frac{1}{2} * D_{t} * A_{t}* p_{t}* v_{t}^{2}$

$F_{t1} = \frac{1}{2} * 0.28 * 0.7m^{2} * 1.2\frac{kg}{m^{3} }* 21.38^{2}= 53.75 N$

$F_{t1} = \frac{1}{2} * 0.28 * 0.7m^{2} * 1.2\frac{kg}{m^{3} }* 29.44^{2}= 101.92 N$

b).

ρ $= 1.2 \frac{kg}{m^{3} }$ , $A_{h}= 2.44 m^{2}$ , $D_{h}= 0.57$

$F_{t1} = \frac{1}{2} * D_{h} * A_{h}* p_{h}* v_{h}^{2}$

$F_{t1} = \frac{1}{2} * 0.57 * 2.44 m^{2} * 1.2\frac{kg}{m^{3} }* 21.38^{2}= 381.44 N$

$F_{t1} = \frac{1}{2} * 0.57 * 2.44 m^{2} * 1.2\frac{kg}{m^{3} }* 29.44^{2}= 723.25 N$

6 0

2 years ago

How many neutrons are in an atom of carbon with a mass number of 13

BabaBlast [244]

C is the answer to your question.

4 0

2 years ago

If a range hood removes contaminants at a flow rate of F liters of air per second, then the percent P of contaminants that are

podryga [215]

Explanation:

The given value of P is as follows.

P = 1.06F + 22.18, $10 \leq F \leq 70$

or, P' = 1.06

As p' is defined and non-zero. Hence, only critical points are boundary points.

For F = 10, the value of P will be calculated as follows.

P = $1.06 \times 10 + 22.18$

= 32.78

For F = 70, the value of P will be calculated as follows.

P = $1.06 \times 70 + 22.18$

= 96.38

Therefore, the minimum value of P is 32.78 and maximum value of P is 96.38.

3 0

2 years ago

How much force is required to accelerate a 50 kg mass at 2 m/s

marta [7]

Answer:

F = 100 Newtons

Explanation:

F = ma

F = (50 kg)(2 m/s)

F = 100 kg*m/s

3 0

2 years ago