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choli [55]
3 years ago
10

Which if the following elements has atoms with the least amount of valence electrons

Chemistry
1 answer:
Fynjy0 [20]3 years ago
3 0
Potassium (K) only has one valence electron. infact, all of the elements in the first column of the periodic table have only one valence electron.  
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Glacial erratic are formed  ice erosion resulting from the movement of ice.  Glacial erratic are composed of ice.
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I need help with this ASAP
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Answer: I dunno that but u should give me brainliest

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What's the basic oxide​
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Basic oxides are oxides that show basic properties in opposition to acidic oxides and that either react with water to form a base; or react with an acid to form a salt and water which are called neutralization reactions.

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Match the following aqueous solutions with the appropriate letter from the column on the right. Assume complete dissociation of
Serhud [2]

Answer:  0.17 m CH_3COONH_4 : Highest freezing point

0.20 m CoSO_4: Second lowest freezing point

0.18 m MnSO_4: Third lowest freezing point

0.42 m ethylene glycol: Lowest freezing point

Explanation:

Depression in freezing point  is a colligative property which depend upon the amount of the solute.

\Delta T_f=i\times k_f\times m

where,

\Delta T_f = change in freezing point

i= vant hoff factor

k_f = freezing point constant

m = molality

a) 0.17 m CH_3COONH_4

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i =2 for CH_3COONH_4, thus total concentration will be 0.34 m

b) 0.18 m MnSO_4

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for MnSO_4, thus total concentration will be 0.36 m

c) 0.20 m CoSO_4

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for CoSO_4, thus total concentration will be 0.40 m

d) 0.42 m ethylene glycol

For non electrolytes undergoing no dissociation, vant hoff factor is equal to 1 . Thus i = 1 for ethylene glycol, thus concentration will be 0.42 m

The more is the concentration, the highest will be depression in freezing point and thus lowest will be freezing point.

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3 years ago
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Anarel [89]

1.55 g/L; 9.503 03 × 10^20 mL

<em>Part 1. </em>

<em>Step 1</em>. Convert <em>kilograms to grams</em>.

1.55 kg × (1000 g/1 kg) = 1550 g

<em>Step 2</em>. Convert <em>cubic metres to litres</em>.

1 m^3 × (1000 L/1 m^3) = 1000 L

<em>Step 3</em>. Divide <em>grams by litres</em>

1.55 kg/1 m^3 = 1550 g/1000 L =  1.55 g/L

<em>Part 2.</em>

<em>Step 1</em>. Convert <em>cubic kilometres  to cubic metres</em>

950 303 km^3 × (1000 m/1 km)^3 = 9.503 03 × 10^14 m^3

<em>Step 2</em>. Convert <em>cubic metres to litres</em>.

9.503 03 × 10^14 m^3 × (1000 L/1 m^3) =  9.503 03 × 10^17 L

<em>Step 3</em>. Convert <em>litres to millilitres</em>.

9.503 03 × 10^17 L × (1000 mL/1 mL) = 9.503 03 × 10^20 mL

8 0
4 years ago
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