Perimeter (P) = 2 · Length(L) + 2 · Width (W) → P = 2L + 2W
Solve for either L or W (I am solving for L).
200 - 2W = 2L
(200 - 2W)/2 = L
100 - W = L
Area (A) = Length (L) · Width (W)
= (100 - W) · W
= 100W - W²
Find the derivative, set it equal to 0, and solve:
dA/dW = 100 - 2W
0 = 100 - 2W
W = 50
refer to the equation above for L:
100 - W = L
100 - 50 = L
50 = L
Dimensions for the maximum Area are 50 ft x 50 ft
The answer is three hundred
Answer:
4 pairs of sock and a little bit of left over change.
Step-by-step explanation:
24.95 + 5.95x = 50
-24.95 -24.95
5.95x=25.05
/5.95 /5.95
x = 4.21
We drop the 0.21 because you cant have 0.21 pairs of socks and we get:
x=4
Answer:
5x-3p
Step-by-step explanation:
(1/3)(3x-6p) + 4x - p
Distribute the 1/3 to the variables in parenthesis.
x - 2p +4x - p
Combine the like variables.
5x - 3p
Hope this helps!