Question

A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h=-16t^2+48t+6. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height? a. 3 s; 6 ft b.1.5 s; 54 ft c. 1.5 s; 114 ft d. 1.5 s; 42 ft

Answer 1

time = -48/(2*-16) = 1.5 seconds

height = -16(1.5)^2+48(1.5)+6 = 42 ft