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Scrat [10]
3 years ago
8

A skier (down a straight course) is able to enter the starting gate with a speed of 1 m/sec and the average acceleration down th

e hill was 3 m/s2. If the skier covers the course in 10 sec, how fast was he moving at the bottom of the course
Physics
1 answer:
ziro4ka [17]3 years ago
7 0
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Which wave lies adjacent to the low frequency portion of the visible spectrum
fgiga [73]

Answer: b. infrared

Explanation:

The visible light with the smaller frequency is associated with the color red.

While the blue is the one with the larger frequency.

Now, as the name says, infrared waves are the ones with a frequency just below the one of the red visible light.

Where the frequency of the red light is something around (4.3*10^14 Hz)

and the frequency of the infrared waves is in the range between (10^12 Hz and 10^14 Hz)

Then the correct option is b, infrared.

8 0
3 years ago
On an aircraft carrier, a jet can be catapulted from 0 to 240 km/h in 2.10 s. If the average force exerted by the catapult is 9.
Leya [2.2K]
<h2>Answer</h2>

The answer is 29495.3 kg

<h2>Explanation</h2>

As we know, the Newton's Second Law of Motion

Force = Mass * Acceleration

F = ma

The F exerted by catapult = 9.35 * 10^5

The Time is = 2.10 s

Velocity of the catapult = 240 km/h = 66.6 m/s   (240*1000 m /3600 s)

The mass of jet = ?

First detrmine the acceleration as

{/tex}Acceleration = Velocity/Time {/tex}

Acceleration = 66.6 ms^{-1}/2.1 s

Acceleration (a) =  31.7 ms^{-2}

Rearrange the formaula as

m= F/a

m= 9.35 * 10^5 N /31.7 ms^{-2}

m = 29495.3 kg

The mass will be 29495.3 kg

4 0
4 years ago
A soccer player kicks a ball from the ground with a speed of 16 m/s at an angle of 63°.
stepladder [879]

A. Horizontal component: 7.3 m/s

Explanation:

The horizontal component of the velocity is given by:

v_x = v_0 cos \theta

where

v_0 = 16 m/s is the magnitude of the initial velocity

\theta=63^{\circ} is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

v_x = (16 m/s) cos 63^{\circ}=7.3 m/s

B. Vertical component: 14.3 m/s

Explanation:

The vertical component of the velocity is given by:

v_y = v_0 sin \theta

where

v_0 = 16 m/s is the magnitude of the initial velocity

\theta=63^{\circ} is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

v_y = (16 m/s) sin 63^{\circ}=14.3 m/s

6 0
3 years ago
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