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8_murik_8 [283]
3 years ago
13

? If you are not moving, Newton's First Law says you

Physics
2 answers:
Rama09 [41]3 years ago
8 0

Newton's First Law states that when an object is not in motion, it will stay motionless until a force is acted upon it. In this case, you are not moving, so unless a force acts upon you, you will stay in place.

spin [16.1K]3 years ago
6 0

Answer:

It will stay still

Explanation:

You might be interested in
Which is an example of a vector quantity
swat32

Answer:

The answer to your question is C

Explanation:

acceleration is a vector quantity because it has both magnitude and direction

4 0
3 years ago
Determine the acceleration that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object
user100 [1]

For 3 kg mass: <em>F = \lpha ma,a = \frac{F}{m} = \frac{12N}{3kg} = 4\lpha m / s^{2}</em>

For 6 kg mass: <em>F = \lpha ma,a = \frac{F}{m} = \frac{12N}{6kg} = 2\lpha m / s^{2}</em>


Hope this helped, have a great day!~

3 0
3 years ago
Two resistors, R1 and R2, are
Aleonysh [2.5K]

Answer:

The value of R₂ is equal to 24.75 ohms.

Explanation:

Given that,

Two resistors, R₁ and R₂, are  connected in parallel.

The equivalent resistance is 14.5 ohms

We need to find the value of R₂.

When two resistors are connected in parallel. The equivalent resistance is given by :

\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{14.5}=\dfrac{1}{35}+\dfrac{1}{R_2}\\\\\dfrac{1}{R_2}=\dfrac{1}{14.5}-\dfrac{1}{35}\\\\\dfrac{1}{R_2}=0.04039\\\\R_2=\dfrac{1}{0.04039}\\\\R_2=24.75\ \Omega

So, the value of R₂ is equal to 24.75 ohms.

8 0
3 years ago
PLS ANSWER ASAP
vivado [14]

Answer:

Cart A

Explanation:

Momentum can be computed by finding the product of mass and velocity. To solve this, you can use the formula below to find the greatest momentum:

p = mv

where:

p = momentum (kgm/s)       m = mass (kg)         v = velocity (m/s)

Because carts are moving along with the weights, we need to consider the whole system. This means that you need to add in the masses and the mass of the cart.

<u>Cart A:</u>

m = 200kg + 0 kg = 200 kg

v = 4.8 m/s

p = 200kg x 4.8 m/s = 960 kg-m/s

<u>Cart B:</u>

m = 200kg + 20 kg = 220 kg

v = 4.0 m/s

p = 220kg x 4.0 m/s = 880 kg-m/s

<u>Cart C:</u>

m = 200kg + 40 kg = 240 kg

v = 3.8 m/s

p = 240kg x 3.8 m/s = 912 kg-m/s

<u>Cart D:</u>

m = 200kg + 60 kg = 260 kg

v = 3.5 m/s

p = 260kg x 3.5 m/s = 910 kg-m/s

As you can see, Cart A has the greatest momentum.

5 0
3 years ago
Read 2 more answers
High speed stroboscopic photographs show that the head of a 244 g golf club is traveling at 57.6 m/s just before it strikes a 45
almond37 [142]

Answer:

The speed will be "1.06 m/s".

Explanation:

The given values are:

Momentum,

m1 = 244 g

m2 = 45.2 g

On applying momentum conservation ,

Let v2 become the final golf's speed.  

From Momentum Conservation

⇒  Total \ initial \ momentum = Total \ final \ momentum

⇒  m1\times u1 + m2\times u2 = m1\times v1 + m2\times v2

On putting the estimated values, we get

⇒  0.244\times 57.6+0=0.244\times 39.9+45.2\times v2

⇒  57.844+0=9.7356+45.2\times v2

⇒  48.1084=45.2\times v2

⇒  v2=\frac{48.1084}{45.2}

⇒  v2=1.06 \ m/s

6 0
3 years ago
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