Question

A soccer player kicks a ball from the ground with a speed of 16 m/s at an angle of 63°.

Answer 1

A. Horizontal component: 7.3 m/s

Explanation:

The horizontal component of the velocity is given by:

$v_x = v_0 cos \theta$

where

$v_0 = 16 m/s$ is the magnitude of the initial velocity

$\theta=63^{\circ}$ is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

$v_x = (16 m/s) cos 63^{\circ}=7.3 m/s$

B. Vertical component: 14.3 m/s

Explanation:

The vertical component of the velocity is given by:

$v_y = v_0 sin \theta$

where

$v_0 = 16 m/s$ is the magnitude of the initial velocity

$\theta=63^{\circ}$ is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

$v_y = (16 m/s) sin 63^{\circ}=14.3 m/s$