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3 years ago

A TV set shoots out a beam of electrons. The beam current is 10A. How many electrons strike the TV screen in a minute.

Physics

2 answers:

Wittaler [7]3 years ago

4 0

Answer:

600 mC

Explanation:

The charge of an electron is 1.6 x 10-19C so for a current with 10 mA, the charge going to screen in one second is 10 mC

so number of electrons, n = (10 x 10-3)/(1.6 x 10-19) = 6.25 x 1016 so in a minute the charge is 10 * 60 = 600 mC

denpristay [2]3 years ago

3 0

Answer:

Total charge, q = It = 10 A x 60 s = 600 C

We know that, q = ne

So no. of electrons, n = q/e = 600 / (1.6×10-19) = 375x1019

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A bubble of air is rising up through the ocean. When it is at a depth of 20.0 m below the surface, where the temperature is 5.00

kotegsom [21]

Answer:

the volume is 0.253 cm³

Explanation:

The pressure underwater is related with the pressure in the surface through Pascal's law:

P(h)= Po + ρgh

where Po= pressure at a depth h under the surface (we assume = 1atm=101325 Pa) , ρ= density of water ,g= gravity , h= depth at h meters)

replacing values

P(h)= Po + ρgh = 101325 Pa + 1025 Kg/m³ * 9.8 m/s² * 20 m = 302225 Pa

Also assuming that the bubble behaves as an ideal gas

PV=nRT

where

P= absolute pressure, V= gas volume ,n= number of moles of gas, R= ideal gas constant , T= absolute temperature

therefore assuming that the mass of the bubble is the same ( it does not absorb other bubbles, divides into smaller ones or allow significant diffusion over its surface) we have

at the surface) PoVo=nRTo

at the depth h) PV=nRT

dividing both equations

(P/Po)(V/Vo)=(T/To)

V=Vo*(Po/P)(T/To) = 0.80 cm³ * (101325 Pa/302225 Pa)*(277K/293K) = 0.253 cm³

V = 0.253 cm³

3 0

3 years ago

PLS HELP ASAP :(( You observe a car parked on the side of the road. If the car started to move, Which conclusion could you make?

Nostrana [21]

Answer:

The first option

Explanation:

7 0

2 years ago

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Determine the diameter of the largest circular hole that can be punched into a sheet of polystyrene 6 mm thick, knowing that the

Yakvenalex [24]

Answer:

43.41 mm

Explanation:

Given:

thickness of sheet, t = 6 mm

Force exerted by punch, F = 45 KN

Average shearing stress, T = 55 MPa

From average shearing stress T = Force F / Area A

Hence area = force/stress =45000/ 55 = $818.18 mm^2$

From area = pi*diameter*thickness

diameter = area/(pi* thickness)

= 818.18/(3.142*6)

= 43.41 mm

4 0

3 years ago

Help plzz!!

frez [133]

Answer: It would be 125 J

4 0

2 years ago

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John drives a distance of 90 Km to the right at a steady speed of V1=25.00 m/s. Then he stops at the gas station for 10 minutes.

aleksley [76]

a. Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

b. $t=6000\ s$ is the total time taken in the trip

c. $d=126000\ m$ is the total distance

d. $s=54000\ m$ towards right from the starting point.

e. $v_a=21\ m.s^{-1}$

f. $\vec v_a=9\ m.s^{-1}$ towards right.

Explanation:

Speed is a scalar quantity while velocity is a vector quantity.

Speed is defined as rate of change of distance per unit time whereas velocity is defined as rate of change of displacement per unit time.

Speed is a directionless quantity while velocity constitutes direction.

Total time of round trip when we're given:

distance travelled to the right, $d_r=90000\ m$

speed while travelling to the right, $v_r=25\ m.s^{-1}$

time spent at gas station, $t_g=600\ s$

time spent while travelling back towards the left, $t_l=30\times 60=1800\ s$

speed while travelling to the left, $v_{_l}=20\ m.s^{-1}$

Now time taken for travelling towards right:

$t_r=\frac{d_r}{v_r}$

$t_r=\frac{90000}{25}$

$t_r=3600\ s$

Therefore total time taken in the round trip:

$t=t_r+t_l+t_g$

$t=3600+600+1800$

$t=6000\ s$

Now, distance travelled towards left:

$d_l=v_{_l}\times t_l$

$d_l=20\times1800$

$d_l=36000\ m$

Therefore total distance:

$d=d_l+d_r$

$d=36000+90000$

$d=126000\ m$

Now, total displacement:

$s=d_r-d_l$

$s=90000-36000$

$s=54000\ m$ towards right from the starting point.

Average speed:

$v_a=\frac{d}{t}$

$v_a=\frac{126000}{6000}$

$v_a=21\ m.s^{-1}$

Average velocity:

$\vec v_a=\frac{s}{t}$

$\vec v_a=\frac{54000}{6000}$

$\vec v_a=9\ m.s^{-1}$ towards right.

4 0

2 years ago