3 years ago

I have questions for 1~5. Thanks

1 answer:

5 0

9888888888888999999999999999999999999999999999999999999999999999900000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

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A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa

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Answer

given,

current (I) = 16 mA

circumference of the circular loop (S)= 1.90 m

Magnetic field (B)= 0.790 T

S = 2 π r

1.9 = 2 π r

r = 0.3024 m

a) magnetic moment of loop

M= I A

M= $16 \times 10^{-3} \times \pi \times r^2$

M= $16 \times 10^{-3} \times \pi \times 0.3024^2$

M= $4.59 \times 10^{-3}\ A m^2$

b) torque exerted in the loop

$\tau = M\ B$

$\tau = 4.59 \times 10^{-3}\times 0.79$

$\tau = 3.63 \times 10^{-3} N.m$

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mrs_skeptik [129]

I think the answer is size

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If a box of supplies is dropped from the cargo hold of an airplane travelling at an altitude of 4,410 meters how long will it ta

Paraphin [41]

Answer:

It will take 30 seconds to reach the ground, and it will be travelling at 294 m/s when it does so. This means that its average velocity was 147 m/s.

Explanation:

$d=v_ot+\dfrac{1}{2}at^2$

Since the initial velocity of a dropped object is 0, we can make this the equation:

$d=\dfrac{1}{2}at^2 \\\\4410=\dfac{1}{2}(9.8)t^2 \\\\t^2=900$

$t=30\text{ seconds}$

The final velocity can be calculated with the formula:

$v_f=v_o+at$

Once again, since there is no initial velocity:

$v_f=at \\\\v_f=(9.8)(30)=294m/s$

Since the initial velocity is 0, the average vertical velocity is 294/2=147 m/s.

Hope this helps!

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Answer:

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A large truck traveling at +15 m/s collides head-on with a small car traveling at -15 m/s, which of the following statements is

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