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aliina [53]
3 years ago
5

I drop a meter stick , and catch it as it falls. If it fell exactly 22 cm, how much did it take me to catch the meter stick (wha

t was my reaction time)?
Physics
1 answer:
statuscvo [17]3 years ago
3 0
D=Vot+1/2at^2

In this case, there is no initial y velocity so the term Vot=0 so d=1/2at^2

acceleration=acceleration due to gravity=-9.8m/s^2

It falls - 22cm or -0.22m

We have - 0.22=1/2(-9.8)t^2

t^2=(-0.44)/(-9.8)

t=sqrt[0.44/9.8]
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The circuit below contains an ideal battery, four identical light bulbs, and a switch. The switch is initially open.
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The question is incomplete! circuit figure is attached below and answer and explanation is provided below.

Answer:

Bulb_A = Bulb_B = Bulb_D and Bulb_C = 0.

Explanation:

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What happens in a series circuit?

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Brightness in a series circuit:

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Answer:

a) d₁ = 247.8 μm

d₂ = 205.3 μm

b) d₂ = 20.53 x 10⁻⁵ m = 205.3 μm

Explanation:

a)

The formula for Michelson Interferometer is derived to be:

d = mλ/2

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d = distance moved

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λ = wavelength of light

For JAN, we have following data

d = d₁

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Therefore,

d₁ = (818)(606 x 10⁻⁹ m)/2

<u>d₁ = 24.78 x 10⁻⁵ m = 247.8 μm</u>

For LINDA, we have following data

d = d₂

m = 818

λ = 502 nm = 502 x 10⁻⁹ m

Therefore,

d₂ = (818)(502 x 10⁻⁹ m)/2

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b)

The resultant displacement can be found out from the difference between both displacement. And the direction of resultant displacement will be the same as the direction of greater displacement. Therefore,

Resultant Displacement = Δd = d₁ - d₂

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<u>Δd = 42.5 μm (in the direction of JAN)</u>

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3 years ago
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