Question

A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed parallel to the plane of the loop.(a) Calculate the magnetic moment of the loop.mA · m2(b) What is the magnitude of the torque exerted by the magnetic field on the loop?mN · m

Answer 1

Answer

given,

current (I) = 16 mA

circumference of the circular loop (S)= 1.90 m

Magnetic field (B)= 0.790 T

S = 2 π r

1.9 = 2 π r

r = 0.3024 m

a) magnetic moment of loop

    M= I A

    M=$16 \times 10^{-3} \times \pi \times r^2$

   M=$16 \times 10^{-3} \times \pi \times 0.3024^2$

   M=$4.59 \times 10^{-3}\ A m^2$

b)  torque exerted in the loop

 $\tau = M\ B$

 $\tau = 4.59 \times 10^{-3}\times 0.79$

 $\tau = 3.63 \times 10^{-3} N.m$