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Anika [276]
4 years ago
15

When Kevin pulls his cotton shirt off his body, the electrons get transferred from the (shirt or body) to the (shirt or body) .

So, the shirt becomes (positively or negatively) charged and Kevin’s body becomes (positively or negatively) charged.
Physics
2 answers:
marissa [1.9K]4 years ago
8 0
Kevin’s body became possessively charged
nignag [31]4 years ago
4 0

Answer:

When Kevin pulls his cotton shirt off his body, the electrons get transferred from the body to the shirt. So, the shirt becomes negatively chargedand Kevin's body becomes positively charged.

Explanation:

All right here we go, we are talking of a phenomenon popularly known as statics. Which occurs due to the friction of the cloth and the body. The fabric friction generates an exchange of electrons in which the electrons jump from the atoms waves of the clothing molecules to our atoms inside our molecules and we obtain an electric charge.

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Answer:

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Also E being constant, can be taken out of integral.

So, E(4πr2)=q0q

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3 years ago
Why does the hood of a car heat up after the car has been running for a while? A) According to the fourth law of thermodynamics,
Svetlanka [38]

Answer:

C) According to the second law of thermodynamics, not all energy from the burnt fuel is used to do work on the piston. It also produces heat which warms other parts of the car.  

Explanation:

A) According to the fourth law of thermodynamics, the temperature of the other parts of the car increases due to the coolant used for the engine.  

B) According to the first law of thermodynamics, the hood of the car heats up using heat from the surroundings in-order to achieve thermal equilibrium with the engine.  

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D) According to the third law of thermodynamics, the increase in the velocity of the car changes the entropy of the tires. To balance this change, the temperature of the other parts is increased.

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4 years ago
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The water in a tank is pressurized by air, and the pressure is measured by a multifluid manometer as shown in Figure below.. Det
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5 0
3 years ago
The following equation is an example of decay?<br><br> 232/90 TH---4/2 HE +228/88 RA?
DaniilM [7]

Answer:

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Explanation:

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5 0
3 years ago
a body initially at rest, starts moving with a constant acceleration of 2ms-2 .calculate the velocity acquired and the distance
Marta_Voda [28]

a) 10 m/s

b) 25 m

Explanation:

a)

The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:

v=u+at

where

u is the initial velocity

v is the final velocity

a is the acceleration

t is the time

For the body in this problem:

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

t = 5 s is the time

So, the final velocity is

v=0+(2)(5)=10 m/s

b)

In this second part, we want to calculate the distance travelled by the body.

We can do it by using another suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the distance travelled

Here we have

u = 0 (the body starts from rest)

a=2 m/s^2 is the acceleration

v = 10 m/s is the final velocity

Solving for s,

s=\frac{10^2-0^2}{2(2)}=25 m

3 0
3 years ago
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