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LekaFEV [45]
2 years ago
8

A box contains plain pencils and 7 pens. A second box contains 6 colored pencils and 2 crayons. One item from each box is chosen

at random. What is the probability that a plain pencil from the first box and a color pencil from the second box are selected? Write your answer as a fraction.
Mathematics
2 answers:
kondaur [170]2 years ago
3 0

Answer:

it is 3 as a simplified fraction

Step-by-step explanation:

BOX 1) 5 plain pencils and 7 pens.  

BOX 2) 6 color pencils and 2 crayons.  

Plain pencil (first box) ~  5 : 7  

Color pencil (second box) ~ 6 : 2  

Simplify.  

3 : 1   <== Second box

arlik [135]2 years ago
3 0
The person above me is right I got the answer correct
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galina1969 [7]

Answer:

See below ~

Step-by-step explanation:

⇒ 65 = 65 + y (alternate exterior angles)

⇒ y = 0

⇒ 4(12x + 1) + 15 = 180 - 65 - y (Linear angles)

⇒ 48x + 4 = 100 - 0

⇒ 48x = 96

⇒ x = 2

⇒ 3(7z + 6) + 5(5z + 1) = 115 (Both the angles are equal "alt. ext. angles")

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3 0
2 years ago
Read 2 more answers
An airline's public relations department claims that when luggage is lost, 88% is recovered and delivered to its owner within 24
melisa1 [442]

Answer:

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

Step-by-step explanation:

Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88

At the null hypothesis, we test if the proportion is of 0.88, that is:

H_0: p = 0.88

At the alternate hypothesis, we test if this proportion is less than 0.88, that is:

H_a: p < 0.88

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.88 is tested at the null hypothesis:

This means that \mu = 0.88, \sigma = \sqrt{0.88*0.12}

A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.

This means that n = 160, X = \frac{138}{160} = 0.8625

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.8625 - 0.88}{\frac{\sqrt{0.88*0.12}}{\sqrt{160}}}

z = -0.68

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.8625, which is the p-value of z = -0.68.

Looking at the z-table, the p-value of z = -0.68 is of 0.2483.

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

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Answer:

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Answer:

I think is C.............

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Answer:

5,589,000

Step-by-step explanation:

5.589 x 1,000,000=

5,589,000

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