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Maurinko [17]
3 years ago
12

What is the inequality for this verbal description?Sam has d dollars to spend on grapes and carrots. He wants to buy one bag of

grapes for $4.00 and c pounds of carrots that cost $2.00 per pound. Which inequality represents this situation?
Mathematics
1 answer:
lesantik [10]3 years ago
7 0
4+2c<=d
this tells us that $4 for grapes plus c bags of carrots that are $2 per pound will give us his total. he wants this to be less than or equal to d.

if able please vote brainliest if you like my response! thanks
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7=-1/4+b solve for b
Svet_ta [14]

Answer:

b = 7 1/4

Step-by-step explanation:

7 = -1/4 + b  

Add 1/4 to both sides

7 1/4 = b

b = 7 1/4

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Express 0.008 in value words
enot [183]

0.008 = eight thousandths

Hope it helps

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3 years ago
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Use the substitution u = tan(x) to evaluate the following. int_0^(pi/6) (text(tan) ^2 x text( sec) ^4 x) text( ) dx
Rudiy27
If we use the substitution u = \tan x, then du = \sec^2 {x}\ dx. If you try substituting just u and du into the integrand, though, you'll notice that there's a \sec^2x left over that we have to deal with.

To get rid of this problem, use the identity \tan^2 x + 1 = \sec^2 x and substitute in the left side of the identity for the extra \sec^2x, as shown:

\int\limits^{\pi/6}_0 {tan^2 x \ sec^4 x} \, dx
\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx

From there, we can substitute in u and du, and then evaluate:

\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx
\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^2(u^2 + 1)} \, du
\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^4 + u^2} \, du
= \left.\frac{u^5}{5} + \frac{u^3}{3}\right|_0^\frac{1}{\sqrt{3}}
= (\frac{(\frac{1}{\sqrt{3}})^5}{5} + \frac{(\frac{1}{\sqrt{3}})^3}{3}) - (\frac{(0)^5}{5} + \frac{(0)^3}{3})
= \frac{1}{45\sqrt{3}} + \frac{1}{9\sqrt{3}} = \frac{6}{45\sqrt{3}} = \bf \frac{2}{15\sqrt{3}}


8 0
3 years ago
Is there any number that when added to 0 is negative, and when subtracted by 0 is also negative?
bogdanovich [222]

Answer:

Subtracting with zero: 0 – a = –a. Use the rule for subtracting signed numbers: Change the operation from subtraction to addition and change the sign of the second number. Likewise, a – 0 = a. It doesn’t change the value of a to subtract zero from it.

Step-by-step explanation:

6 0
3 years ago
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Let f(x) = |x|, ????(x) = 2f(x), and h(x) = 1 / 2 f(x) for any real number x.
SashulF [63]

Answer:

g(x) = 2|x|

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Step-by-step explanation:

If you have g(x)=2f(x) and h(x)=\frac{1}{2}f(x), you can rewrite the expressions in terms of |x| as the following:

- For g(x)=2f(x) you have:

g(x) = 2|x|

-For h(x)=\frac{1}{2}f(x), you have:

h(x) = \frac{1}{2}|x|

8 0
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