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Flura [38]
2 years ago
6

Sue took a test in both biology and math last week. The biology test had a mean of 70 and a standard deviation of 7 whereas the

math test had a mean of 75 and a standard deviation of 10. Sue scored a 76 on the biology test and a 76 on the math test. On which test did she do better in comparison to the rest of the class?​Select one:a. she did the same on each testb. the math testc. the biology testd. cannot be determined
Mathematics
1 answer:
Anna [14]2 years ago
6 0

Answer:

c. the biology test

Step-by-step explanation:

To answer this problem we need to calculate the z-score of both tests, using the formula:

z = (x - μ) / σ

Where x is Sue's score, μ is the mean, and σ is the standard deviation.

  • For the <u>biology test</u>, the z-score is:

z = (76 - 70) / 7 = 6/7 = 0.857

  • For the <u>math test</u>, the z-score is:

z = (76 - 75) / 10 = 1/10 = 0.100

Because the z-score for the biology test is greater than the z-score for the math test, Sue did better in the biology test, in comparison to the rest of the class.

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Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is  x = 274 \ unites

Step-by-step explanation:

From the question we are told that

       The length of the vertical length is  x

      The length of the base leg is L = 330 + d units

      The length of the bisecting line segment is h

       The base angle is \theta  = 28^o

       The angle between d and line segment is  \theta_1 =  56^o

For the first angle

         Tan \theta_1 =  \frac{x}{d}

=>     d =  \frac{x}{Tan \theta _1}

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=>     d = \frac{x}{Tan \theta }  -330

So equating the both d

        \frac{x}{Tan \theta _1} =    \frac{x}{Tan \theta }  -330

Substitute values

        \frac{x}{Tan (56)} =    \frac{x}{Tan (28) }  -330

      0.6745 x =    1.880x  -330

       1.20549 x = 330

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Answer:

y

=

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1

Explanation:

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1

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1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

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and

(

x

2

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2

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m

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+

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4

2

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=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer linky

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

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(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer link

4 0
2 years ago
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