Y = 2x³, when x = -3
<span>y = 2*(-3)³
</span>
<span>y = 2*-27
</span>
y = -54
It appears that you have a derivative and want to integrate...
dy/dx=1+3√x
y(x)=x+(2/3)x^(3/2)+C you are given that f(4)=25 so we can solve for the constant of integration...
y(4)=25=4+16/3+C
21=16/3+C
(63-16)/3=C
47/3=C so
f(x)=x+(2/3)x^(3/2)+47/3
f(x)=(3x+2x^(3/2)+47)/3
Answer:
6
Step-by-step explanation:
I used the formula d=√((x_2-x_1)²+(y_2-y_1)²), plugged in the numbers and solved and got 6 units.
16 because 36 divided by 9 is 4 so you have to multiply the 4 x 4
- 5x - 4x + 24 = - 3
9x = 27
x = 3