3. A, (first choice)
4. C (Third choice from top)
Answer:
Answered below.
Explanation:
The three general methods consist of unicasting, broadcasting and multicasting.
Casting implies the transfer of data from one computer (sender) to another (recipient).
Unicasting is the transfer of data from a single sender to a single recipient.
Broadcasting deals with the transfer of data from one sender to many recipients.
Multicasting defines the transfer of data from more than one sender to more than one recipients.
The second one, it should be the one that is opening left with a line underneath, the images are unclear but that’s the most likely correct answer !
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
Answer: (66.7_1.8)Ω
Explanation: Hope it's helpful
