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Kaylis [27]
4 years ago
10

Jeremy pulled on the spring scale below. how could he decrease the force needed?

Physics
1 answer:
rosijanka [135]4 years ago
5 0
Well since decrease me and down he could use his pulling force with a little less force.
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What are the four types of musical instruments and what are the physical behind each type of musical instrument
pishuonlain [190]

Answer:

The four types of musical instruments are percussion, woodwind, brass, and strings.

Explanation:

Percussion instruments include drums, triangle, cymbals, and xylophones. There are more instruments than what i've mentioned though. Percussion instruments often produce the beat of songs.

Woodwind instruments include clarinets, oboe, flute, and saxophone. Woodwind instruments often produce the harmony of songs and, occasionally, the melody.

Brass instruments include trumpet, trombone, french horn, and tuba. Brass instruments often produce the harmony of songs, the trumpet produces the melody a lot though.

String instruments include guitars, violins, cello, bass, ukulele, and banjo. String instruments produce both the harmony and the melody. These instruments often produce really beautiful music, in my opinion.

8 0
3 years ago
You may make the following measurements of an object 42kg and 22m3. What would the objects density be?
ki77a [65]
Density=mass/volume
to find the density
mass=42kg
volume=22m3
so density=42/22
density=1.9Kgm3
8 0
3 years ago
A single polarizer will stop _____ of the incoming light.
True [87]
A single polarizer will stop 50% of the incoming light.
8 0
3 years ago
Read 2 more answers
Hans Langseth's beard measured 5.33 m in 1927. Consider two charges, q1 = 2.42 nC and an unspecified charge, q2, are separated 5
schepotkina [342]

Answer:

-7.89 * 10^(-9) C

Explanation:

Parameters given:

q1 = 2.42 nC = 2.42 * 10^(-9) C

Distance between q1 and q2 = 5.33 m

q3 = 1.0 nC = 1 * 10^(-9) C

Distance between q1 and q3 = 1.9 m

Distance between q2 and q3 = 5.33 - 1.9 = 3.43 m

The net force acting on q3 is:

F = F(q1, q3) + F(q2, q3)

F = (k*q1*q3)/1.9² + (k*q2*q3)/3.43²

F = (9 * 10^(9) * 2.42 * 10^(-9) * 1 * 10^(-9))/3.61 + (9 * 10^(9) * q2 * 1 * 10^(-9))/11.7649

F = 6.033 * 10^(-9) + 0.765*q2

If the net force is zero:

0 = 6.033 * 10^(-9) + 0.765*q2

-0.765*q2 = 6.033 * 10^(-9)

=> q2 = -[6.033 * 10^(-9)]/0.765

q2 = -7.89 * 10^(-9) C

3 0
3 years ago
How much heat is absorbed by a 71g iron skillet when its temperature rises from 11oC to 29oC?
diamong [38]
The right formula to use for this calculation is the heat capacity formula, 
Heat absorbed, Q = MCT, Where 
M = Mass of the substance = 71
C = Specific heat capacity for iron = 0.450 J/gc
T = Change in temperature = 29 - 11 = 18
Q = 71 * 0.450 *18 = 575.10
The amount of heat absorbed by the iron skillet is 575 J.
5 0
3 years ago
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