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olga nikolaevna [1]
3 years ago
5

A 140 g ball at the end of a string is revolving uniformly in a horizontal circle of radius 0.537 m. The ball makes 2.27 revolut

ions in a second. What is its centripetal acceleration?
Physics
1 answer:
klio [65]3 years ago
6 0

Answer:

109.13 rad/s^2

Explanation:

m = 140 g = 1.4 kg, r = 0.537 m, f = 2.27 rps

The centripetal acceleration is given by

a = r ω^2

a = r x (2 π f)^2

a = 0.537 x ( 2 x 3.14 x 2.27)^2

a = 109.13 rad/s^2

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In a domestic electric circuit (220.V),an electric kettle of 3kW power rating is operatedthat has a current rating of 4A. What r
kozerog [31]

Answer:

(i) It will take longer (75/22 times) the time to boil a given quantity of water compared to when the current is working at its rated capacity

(ii) The reasons are;

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(2) For safety; to prevent the over heating of the electric circuits when an high electric power appliance needs to be connected an high power electric power outlet has to be specified

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(ii) This is so because the power consumption already factored in the electrical installation as well as the type of appliances utilized in the home allow for several low power rating consumption and few high power rating consumption

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The current required for high power and low power appliances is different and also the fuse rating required for both the appliances different, so two separate circuits are used for high power and low power appliances.

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200 x t = 50x8 - 50x0

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