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olga nikolaevna [1]
3 years ago
5

A 140 g ball at the end of a string is revolving uniformly in a horizontal circle of radius 0.537 m. The ball makes 2.27 revolut

ions in a second. What is its centripetal acceleration?
Physics
1 answer:
klio [65]3 years ago
6 0

Answer:

109.13 rad/s^2

Explanation:

m = 140 g = 1.4 kg, r = 0.537 m, f = 2.27 rps

The centripetal acceleration is given by

a = r ω^2

a = r x (2 π f)^2

a = 0.537 x ( 2 x 3.14 x 2.27)^2

a = 109.13 rad/s^2

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Levart [38]

Explanation:

Let

x_1 = distance traveled while accelerating

x_2 = distance traveled while decelerating

The distance traveled while accelerating is given by

x_1 = v_0t + \frac{1}{2}at^2 = \frac{1}{2}at^2

\:\:\:\:\:= \frac{1}{2}(2.5\:\text{m/s}^2)(30\:\text{s})^2

\:\:\:\:\:= 1125\:\text{m}

We need the velocity of the rocket after 30 seconds and we can calculate it as follows:

v = at = (2.5\:\text{m/s}^2)(30\:\text{s}) = 75\:\text{m/s}

This will be the initial velocity when start calculating for the distance it traveled while decelerating.

v^2 = v_0^2 + 2ax_2

0 = (75\:\text{m/s})^2 + 2(-0.65\:\text{m/s}^2)x_2

Solving for x_2, we get

x_2 = \dfrac{(75\:\text{m/s})^2}{2(0.65\:\text{m/s}^2)}

\:\:\:\:\:= 4327\:\text{m}

Therefore, the total distance x is

x = x_1 + x_2 = 1125\:\text{m} + 4327\:\text{m}

\:\:\:\:= 5452\:\text{m}

3 0
3 years ago
I shoot a bullet up at 270 m/s. How long does it fly for????
IrinaVladis [17]

Answer:

5 minutes

Explanation:

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Two coils are placed close together in a physics lab to demonstrate Faraday’s law of induction. A current of 5.00 A in one is sw
Mariana [72]

Answer:

Mutual inductance will be M=1.8\times 10^{-3}Hennry

Explanation:

We have given induced current \Delta i=5A

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e=M\frac{\Delta i}{\Delta t}

9=M\times \frac{5}{10^{-3}}

M=1.8\times 10^{-3}Hennry

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3 years ago
The angle of incidence for a ray of light passing through the centre of curvature of a concave mirror is.
evablogger [386]

The angle of incidence for a ray of light passing through the center of curvature of a concave mirror is 0°.

The angle of incidence is the angle between the surface's normal and the incident ray. For a concave mirror, the normal of the surface is along the center of the curvature, and a ray of light passed through a center of curvature passes through the normal of the surface.

The ray of light retreats its path making a zero angle of reflection. The law of reflection state that the angle of incidence is equal to the angle of reflection; therefore, the angle of incidence of a concave surface passed through the center of curvature is zero degrees.

Learn more about the  angle of incidence here:

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5 second fall starting at 0 m/s
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