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myrzilka [38]
3 years ago
5

A single polarizer will stop _____ of the incoming light.

Physics
2 answers:
True [87]3 years ago
8 0
A single polarizer will stop 50% of the incoming light.
beks73 [17]3 years ago
8 0
<span>A single polarizer will stop %46 </span><span>of the incoming light.

Good luck!</span>
You might be interested in
QUESTION 1 Linear Motion
Misha Larkins [42]

Answer:

48.51ms / 174.6 km/h

Explanation:

y = 1/2 x g x t^2         v = g x t          

when y = 120m

120 = 1/2 x 9.8 x t^2

t^2 = 24.49

t = 4.95s

when t = 4.95s

v = 9.8 x 4.95

v = 48.51 m/s = 174.6 km/h

I'd say its realistic. But I don't really know that sry

3 0
2 years ago
which actions most likely cause the domains within a material to lose their alignment and become more randomized
zimovet [89]

answer:

heating the material

placing the material in a magnetic field of opposite polarity

hitting the material

4 0
3 years ago
Read 2 more answers
9. If the musician hit the drum on a stage, how would the sound wave behave differently if he hit it the drum if the drum were s
egoroff_w [7]
I think it would be yes because the drum is submerged in water and the water would slow the sound waves, making the sound softer. Right?
4 0
3 years ago
What is the metric unit for time?
spin [16.1K]
The base unit of time in the metric and SI system is the second.
5 0
3 years ago
A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can
Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

\mu is the coefficient of friction between the tires and the road

m is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

v is the speed of the car

r is the radius of the curve

In this problem,

r = 750 m is the radius

v=85 mph \cdot \frac{1609}{3600}=38.0 m/s is the speed

And solving for \mu, we find the coefficient of friction required to keep the car in circular motion:

\mu = \frac{v^2}{rg}=\frac{38.0^2}{(750)(9.8)}=0.196

Learn more about circular motion:

brainly.com/question/2562955  

brainly.com/question/6372960  

#LearnwithBrainly

8 0
3 years ago
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