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beks73 [17]
2 years ago
13

When a satellite is in orbit around the Earth, the force of the gravity on the satellite is...

Physics
1 answer:
lbvjy [14]2 years ago
4 0

Answer:

Is always towards the center of the Earth

Explanation:

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Water flows over a section of Niagara Falls at rate of 1.1×10^6 kg/s and falls 49.4 m. How much power is generated by the fallin
DerKrebs [107]

Answer:

<em>The power generated is =  5.33×10⁸ Watt. </em>

Explanation:

Power: Power can be defined as the time rate of doing work. The S.I unit of power is <em>Watt(W).</em>

<em>Mathematically,</em>

<em>Power (P) = Work done/time or Energy/time</em>

P = mgh/t............................... Equation 1

P = δgh............................. Equation 2

Where δ = fall rate, g = acceleration due to gravity, h = height.

<em>Given: </em>δ = 1.1×10⁶ kg/s, h = 49.4 m g = 9.81 m/s²

Substituting these values into equation 2

P = 1.1×10⁶×49.4×9.81

P = 533.08×10⁶

<em>P = 5.33×10⁸ Watt.</em>

<em>Thus the power generated is =  5.33×10⁸ Watt. </em>

5 0
3 years ago
A powerful motorcycle can produce an acceleration of 3.50 m/s2 while traveling at 90.0 km/h. At that speed the forces resisting
IrinaK [193]

Answer:1265 N

Explanation:

Given

acceleration of motorcycle \left ( a\right )=3.5 m/s^2

Velocity \left ( v\right )=90 km/h\approx 25m/s

Air friction and Friction\left ( f\right )=425 N

mass of the motorcycle with rider\left ( m\right )=240 Kg

Applying Forces on motorcycle

F_{engine}-f=ma

F_{engine}=f+ma

F_{engine}=425+240\left ( 3.5\right )

F_{engine}=425+840=1265 N

5 0
3 years ago
Which of the following is one way of preventing poisoning?
Iteru [2.4K]
I think its number 1

7 0
2 years ago
PLZ Help Me I give you brainlist also NO LONKS OR I REPORT and Have a gr8 day my peeps
Sergio039 [100]

Answer:

the answer is a because I saw it in a syllabus

3 0
3 years ago
A parallel plate capacitor creates a uniform electric field of and its plates are separated by . A proton is placed at rest next
zalisa [80]

Complete Question

A parallel plate capacitor creates a uniform electric field of 5 x 10^4 N/C and its plates are separated by 2 x 10^{-3}'m. A proton is placed at rest next to the positive plate and then released and moves toward the negative plate. When the proton arrives at the negative plate, what is its speed?

Answer:

V=1.4*10^5m/s

Explanation:

From the question we are told that:

Electric field B=1.5*10N/C

Distance d=2 x 10^{-3}

At negative plate

Generally the equation for Velocity is mathematically given by

V^2=2as

Therefore

V^2=\frac{2*e_0E*d}{m}

V^2=\frac{2*1.6*10^{-19}(5*10^4)*2 * 10^{-3}}{1.67*10^{-28}}

V=\sqrt{19.2*10^9}

V=1.4*10^5m/s

5 0
3 years ago
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