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Simora [160]
4 years ago
10

Can you help me With the equation only so I can try to answer them but if you can help me with the answer that’ll be cool too wi

ll give BRAINLIEST and this is due today so PLEASE help

Mathematics
1 answer:
Molodets [167]4 years ago
6 0

Hey there,

#1 is D: 18 men and 30 women. The equation is: 12*m=48

#2 is B: Kathy drove 9 hours and Brain drove 3 hours. The equation is: 65m+55m/12=750

#3 is C: $0.86. The equation is: 2b+1h+1b+2h=8.52

#4 is B : 25 pizzas and 80 sodas. The equation is: 3*4p+5=260

:)

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Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

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4 years ago
If angle∠ A and angle∠ B are supplementary angles and angle∠ A is eighteight times as large as angle∠ ​B, find the measures of a
Shalnov [3]
A = 8B
A + B = 180
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3 years ago
Which expression is equal to sec x° multiplied by cot x°?
Over [174]
Sec x is equal to 1/cosx, cot x is equal to cosx/sinx. cos x cancels, and you are left with 1/sinx. this is equal to cscx. Cosecant is : hypotenuse / opposite, so the answer is **D**
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where:
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thus
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Answer : 942/157 = 6

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