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sergij07 [2.7K]
4 years ago
11

PLZ HELP

Mathematics
1 answer:
Anna35 [415]4 years ago
8 0
A) The list of 6 ordered pairs will be: (0, 9) (1, 8.5) (2, 8) (3, 7.5) (4, 7) (5, 6.5) (6, 6)
Increase x-coordinate by 1 at each instance (time is increasing in hours) and decrease y-coordinate by 0.5 (height is decreasing) 

B) Ordered Pairs: (0, 9) (1, 8.5) (2, 8) (3, 7.5) (4, 7) (5, 6.5) (6, 6)
The<span> y-coordinate is not repeating for different x-values.

C) Ordered Pairs: (0, 9) (1, 8.55) (2, 8.10), (3, 7.65), (4, 7.20), (5, 6.75)
Just as B the y-coordinate is not repeating for different y-'s.I just decreased the y's, so it doesn't affect x-coordinate, and the nature of our function won't change.

Hope It Helps!
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More information for you..

https://youtu.be/V5tUc-J124s

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3 0
3 years ago
Graph each piecewise function. Then identify the properties.
Alexxx [7]

Answer:

Domain: (-∞, -2) U [-2, 1] U (1, ∞)

Range: (-∞, 2) U [-3, -∞)

Step-by-step explanation:

This function is composed of three polynomial functions, a positive slope line m = \frac{1}{2}, whose domain is all real numbers, a horizontal line, and a negative slope line m = -1 whose domain is all real numbers.

Observe in the attached graph that the function has a discontinuity in x = -2, it has a jump.

When x approaches -2 by the left hand, y tends to 2. But when x approaches -2 from the right y tends to -3.

In addition, the function comes from -∞, then has a maximum value at y = 2 and finally derece up to -∞

Then we can conclude that for this piecewise function:

Domain: (-∞, -2) U [-2, 1] U (1, ∞) All Real Numbers

Range: (-∞, 2) U [-3, -∞)

4 0
3 years ago
Me ajudem com a 3º questão
Alisiya [41]

I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.

10 = \dfrac{n(n-3)}{2}

20 = n^2 - 3n

n^2 - 3n - 20 = 0

Answer: n² - 3n - 20 = 0

That doesn't factor so there is no integer n solution.

That means there are no polygons with 10 diagonals.

n = \frac 1 2(3 \pm \sqrt{89})

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