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sergij07 [2.7K]
3 years ago
11

PLZ HELP

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0
A) The list of 6 ordered pairs will be: (0, 9) (1, 8.5) (2, 8) (3, 7.5) (4, 7) (5, 6.5) (6, 6)
Increase x-coordinate by 1 at each instance (time is increasing in hours) and decrease y-coordinate by 0.5 (height is decreasing) 

B) Ordered Pairs: (0, 9) (1, 8.5) (2, 8) (3, 7.5) (4, 7) (5, 6.5) (6, 6)
The<span> y-coordinate is not repeating for different x-values.

C) Ordered Pairs: (0, 9) (1, 8.55) (2, 8.10), (3, 7.65), (4, 7.20), (5, 6.75)
Just as B the y-coordinate is not repeating for different y-'s.I just decreased the y's, so it doesn't affect x-coordinate, and the nature of our function won't change.

Hope It Helps!
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At a real estate​ agency, an agent sold a house for ​$336000. The commission rate is ​5.5% for the real estate agency and the co
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Step-by-step explanation:

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3 0
3 years ago
Please answer this correctly without making mistakes
snow_tiger [21]

Answer:

d = 115.4 mi

Step-by-step explanation:

Since it gives us the distance in between the locations, we simply label the distances:

From the Garbage to the Hotel is 58.3 miles.

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We are trying to find the distance from the Garbage to the Hardware Store, we simply add the distances between:

58.3 mi + 57.1 mi = 115.4 mi

8 0
3 years ago
What is the center of the circle that you can circumscribe about a triangle with vertices A(2, 6), B(2, 0), and C(10, 0)?
denis23 [38]
The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle  (x,y):
d^2 = (x-x_0)^2 + (y-y_0)^2
Plugging in points A and B into distance formula, then setting them equal to each other gives:
(x-2)^2+(y-6)^2 = (x-2)^2 + y^2
Right away we can cancel out the x terms leaving:
(y-6)^2 = y^2
Expand Left side and Solve for y:
y^2 -12y +36 = y^2
y = 3
Plug in points B and C as before:
(x-2)^2 + y^2 = (x-10)^2 + y^2
Here we can cancel the y-terms.
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x^2 -4x+4 = x^2 -20x+100
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6 0
3 years ago
(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions
Sliva [168]
\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}
\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}
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\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}
\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}
\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}
\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0
\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0

this will be continued
5 0
3 years ago
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