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3 years ago

14

Points A,B,C and D are midpoints of the sides of the larger square. If the smaller square has area 60, what is the area of the b

igger square?

1 answer:

kotykmax [81]3 years ago

6 0

Answer:

80

Step-by-step explanation:

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PLEASE HELP ASAP

Leviafan [203]

Answer:

-2/5

Step-by-step explanation:

<h3>Given</h3>

tan (x)=2/5

<h3>To find</h3>

tan (2pi - x)

<h3>Solution</h3>

tan (2pi - x) =
- tan (x) =
- 2/5

Correct choice is B

5 0

3 years ago

Read 2 more answers

Whats gucci someone plesee

sammy [17]

$\frac{2.3 * 10^{-4}}{1.15 * 10^{-8}} = 20000$

Therefore, the answer is D: 20,000

3 0

3 years ago

Read 2 more answers

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

11 months ago

Polygon ABCD is defined by the points A(-4,2) B(-2, 4), C(1, 3) & D(2,2). Match the coordinates of the points of the transfo

dalvyx [7]

Answer:

D'(-2, 2); C''(3, -1); A'''(4, -2); and B''(4, 2)

Step-by-step explanation:

See attachment for the figure.

<u>For D'</u>, rotating the point (2, 2) 90° counterclockwise. This maps each point (x, y)→(-y, x); it takes (2, 2)→(-2, 2).

For C'', rotating the point (1, 3) 90° clockwise. This maps each point (x, y)→(y, -x); it takes (1, 3)→(3, -1).

For A''', rotating the point (-4, 2) 180° clockwise. This maps every point (x, y)→(-x, -y); it takes (-4, 2)→(4, -2).

For B'', rotating the point (-2, 4) 270° counterclockwise. This is the similar as rotating the point 90° clockwise. This maps every point (x, y)→(y, -x); it takes (-2, 4)→(4, 2).

8 0

3 years ago

Andy was given data to draw 3 scatter diagrams.

vredina [299]

Answer:

A) Negative Correlation. B) C. C) B

Step-by-step explanation:

<h2>A:</h2>

As the line of best fit is travelling downwards, it is a negative correlation, if the line of best fit is travelling upwards, it is a positive correlation, if the points on the graph are all over the place, there is no correlation.

<h2>B:</h2>

As there are only three types of correlation, the strongest is always the positive.

<h2>C:</h2>

The answer is B because there is no correlation and that means that there shouldn't be a line of best fit.

6 0

2 years ago