Both rocks hit the ground at the same time and at the same distance from the base of the cliff. Option A is correct.
<h3>What is speed ?</h3>
Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while u for the final speed. its SI unit is m/sec.
If the resistance is ignored, things falling near the Earth's surface have the same estimated acceleration due to gravity of 9.8 meters per second.
As a result, the objects' acceleration is the same, and their velocity is growing at a consistent pace.
So that both rocks hit the ground at the same time and at the same distance from the base of the cliff.
Hence, option A is correct.
To learn more about the sped, refer to the link;
brainly.com/question/7359669
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<span>1. Get a graduated cylinder.
2. Fill the graduated cylinder to a known amount of water. Record the amount of water in the cylinder.
3. Place rock into the graduated cylinder
4. Measure the new volume of the graduated cylinder with the rock in it.
5. Take the difference of the new volume and the old volume and that is the volume of the rock.</span>
Hello
The bullet is moving by uniformly accelerated motion.
The initial velocity is

, the final velocity is

, and the total time of the motion is

, so the acceleration is given by
where the negative sign means that is a deceleration.
Therefore we can calculate the total distance covered by the bullet in its motion using

So, the bullet penetrates the sandbag 1.8 meters.
I notice that even though we're working with frames of reference
here, you never said which frame the '5 km/hr' is measured in.
In fact ! You didn't even say which frame the '12 km/hr' of his
bike is measured in.
So there are several different ways this could go. I'll do it the way
I THINK you meant it, but that doesn't guarantee anything.
-- Simon is riding his bike at 12 km/hr relative to the sidewalk,
away from Keesha.
-- He throws a ball at Keesha, at 5 km/hr relative to his own face.
-- Keesha sees the ball approaching her at (12 - 5) = 7 km/hr
relative to the ground and to her.