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4 years ago

What properties of titanium make it attractive for use in race-car and jet-engine components?

1 answer:

3 0

Titanium's high quality to weight proportion and corrosion protection at room and hoisted temperature makes it appealing for use in elite applications. High cost of titanium is the key purpose behind not utilizing it in traveler autos. The cost of large scale manufacturing of the parts would drive the last items cost fundamentally.

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Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 mi away. He travels at a steady 46.0 mph . Beth leaves Los A

elena-14-01-66 [18.8K]

Answer:

25 min, 48 sec

Explanation:

Alan:

t = d/v

= 400 mi / 46 mph = 8.70 hr

So it took Alan 8.70 hrs; from 8 am, that's 4:42 pm that he arrives.

t = d/v

= 400 mi / 55 mph = 7.27 hr

So it took Beth 7.27 hrs; from 9 am, that's 4:16:12 that she arrives.

4:42 - 4:16:12 = 25.8 minutes = 25 minutes, 48 sec

4 0

4 years ago

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approxim

sergiy2304 [10]

Answer:

10.53m/s²

Explanation:

Centripetal acceleration is the acceleration of an object about a circle. The formula for calculating centripetal acceleration is expressed by:

$a = \frac{v^2}{r}$

v is the velocity of the car = 24.5m/s

r is the radius of the track = 57.0m

Substitute the given values into the formula:

$a = \frac{24.5^2}{57} \\\\a = \frac{600.25}{57}\\ \\a = 10.53m/s^{2}$

Hence the centripetal acceleration of the race car is 10.53m/s²

6 0

3 years ago

Which goes faster? *<br> light in space<br> sound in air<br> sound in space<br> light in water

andrezito [222]

Answer:

Hello! Your answer is, sound in the air is faster

Explanation:

The speed of sound through air is about 340 meters per second. It's faster through water and it's even faster through steel. Light will travel through a vacuum at 300 million meters per second. So they're totally different scales.

Hope I helped! Ask me anything if you have any questions! Brainiest plz. Hope you make an 100% and have a nice day! -Amelia♥

8 0

3 years ago

Oceanographers use submerged sonar systems, towed by a cable from a ship, to map the ocean floor. In addition to their downward

KATRIN_1 [288]

Answer:

Tension in the cable is T = 16653.32 N

Explanation:

Give data:

Cross section Area A = 1.3 m^2

Drag coefficient CD = 1.2

Velocity V = 4.3 m/s

Angle made by cable with horizontal =30 degree

Density $\rho \ of\ water= 1000 kg/m3$

Drag force FD is given as

$F_{D} = \fracP{1}{2} \rho v^{2} C_{D} A$

$= 0.5\times 1000\times 4.32\times 1.2\times 1.3$

Drag force = 14422.2 N acting opposite to the motion

As cable made angle of 30 degree with horizontal thus horizontal component is take into action to calculate drag force

TCos30 = F_D

$T = \frac{F_D}{cos30}$

$T =\frac{ 14422.2}{cos 30}$

T = 16653.32 N

7 0

3 years ago

A car is traveling at 120 km/h (75 mph). When applied the braking system can stop the car with a deceleration rate of 9.0 m/s2.

Bumek [7]

Answer:

the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

Explanation:

Given that;

speed of car V = 120 km/h = 33.3333 m/s

Reaction time of an alert driver = 0.8 sec

Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver will be'

S_d = V × 2.2 sec

S_d = 33.3333 m/s × 2.2 sec

S_d = 73.3333 m

hence, number of car of additional car length n will be;

n = S_n / car length

n = 73.3333 m / 5m

n = 14.666 ≈ 15

Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15

8 0

3 years ago