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Fynjy0 [20]
2 years ago
14

Choose the force diagram (freebody diagram) that best represents the forces acting on the object.

Physics
1 answer:
Levart [38]2 years ago
6 0

Answer:

Diagram B because a plate resting on a table has gravity acting on it and normal/air resistance force working against the gravity with the same amount of force. Forces that are balanced don't move.

Explanation:

I hope this helps

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4. A car accelerates, from rest, at 2.4 m/s?. How fast is the car traveling
pantera1 [17]

Answer:

19.2m/s

Explanation:

Assuming that 2.4m/s^2 was the acceleration and not a typo, we can use the equation v=at, where v=velocity, a=acceleration, and t=time,

plug in known varibles,

v=2.4*8

v=19.2m/s

4 0
2 years ago
Which equations could be used as is, or rearranged to calculate for frequency of a wave? Check all that apply.
amm1812
-- Equations  #2  and  #6  are both the same equation,
and are both correct.

-- If you divide each side by  'wavelength', you get Equation #4,
which is also correct.

-- If you divide each side by  'frequency', you get Equation #3,
which is also correct. 
With some work, you can rearrange this one and use it to calculate
frequency.

Summary:

-- Equations #2, #3, #4, and #6 are all correct statements,
and can be used to find frequency.

-- Equations #1 and #5 are incorrect statements.
7 0
3 years ago
Read 2 more answers
NEED HELP ASAP WILL MARK BRAINLIEST.
-Dominant- [34]
G is the answer for apex vs / Chehhhh
3 0
3 years ago
What is one behavior that a plant has that a human would be suprised by
statuscvo [17]
Growing and being able to pollen

3 0
3 years ago
A coil is connected in series with a 19.0 kΩ resistor. An ideal 50.0 V battery is applied across the two devices, and the curren
Gre4nikov [31]

Answer:

inductance of the coil 29.3767  H

Explanation:

given data

resistor R =  19.0 kΩ = 19 × 10³ Ω

potential applied V  = 50.0 V

current I = 2.20 mA  =  2.20 × 10^{-3} A

time t = 2.80 ms = 2.80 × 10^{-3} s

solution

we know for maximum current in circuit that is

current = V ÷ R   .........1

current =  \frac{50}{19\times 10^3}

current = 2.63 × 10^{-3} A

so at time t = 0

t = -\frac{L}{R} ln(1-\frac{I_f}{I_{max}})  

2.80 \times 10^{-3} = -\frac{L}{19\times 10^3} ln(1-\frac{2.20\times 10^{-3}}{2.63\times 10^{-3}}})  

L = 29.3767

3 0
3 years ago
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