Simon is riding a bike at 12 km/h away from his friend Keesha.He throws a ball at 5 km/h back to Keesha, who is standing still o
1 answer:
You might be interested in
The kinetic energy of the bullet is 20.4 kJ.
<u>Explanation:</u>
Kinetic energy of a bullet will be equal to the product of mass of the bullet with the square of velocity or speed of the bullet and then the half of that product value.
But here the mass of the bullet is not given, instead the weight of the bullet is given in terms of force. So from this, we have to first find the mass of the bullet.
We know that as per Newton's second law of motion, force is directly proportional to the product of mass and acceleration. So here the acceleration will be equal to the acceleration due to gravity as it is weight of the object.
So F = mg
0.10 N = m × 9.8
So ,the mass of the bullet is 0.0102 kg.
Now, we know the mass and velocity of the bullet is given as 2000 m/s.
So,
kinetic energy = × m × v²
kinetic energy = 0.5 × 0.0102 × 2000 × 2000 = 20.4 kJ
Thus, the kinetic energy of the bullet is 20.4 kJ.
Energy is 4 * J
The rate of dissipation is 2 * W
In the question, it is given that
t = 20 s
R = 400 mm
L = 300 mm
where t, R, and L are time, radius, and length.
For magnetic energy density, the formula is
ηo = Energy / volume
= β^2 / 2 * μ
Now, substituting the values
= / 2 * 4 * Π *
= 1.59 * J / m^3
Now, energy is
= energy density * volume
= 1.59 * * Π * 0.5 *
= 4 * J
The rate of dissipation is
= Energy / time
= 4 * / 20
= 2 * W
For more information click on the link below:
# SPJ4