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bogdanovich [222]
4 years ago
13

Aristarchus measured the angle between the Sun and the Moon when exactly half of the Moon was illuminated. He found this angle t

o be A greater than 90 degrees. B exactly 90 degrees. C less than 90 degrees by an amount too small for him to measure. D less than 90 degrees by an amount that was easy for him to measure.
Physics
1 answer:
frutty [35]4 years ago
8 0

Answer:

when the Sun illuminates half of the Moon it must be at 90°

Explanation:

The Moon has a circular motion around the Earth and the relative position of the sun, the earth and the moon create the lunar phases.

For this case when the Sun illuminates half of the Moon it must be at 90°, this angle changes with the movement of the moon, it is zero degree for the new moon and 180° for the full moon

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9. Una jeringa contiene cloro gaseoso, que ocupa un volumen de 95 mL a una presión de 0,96 atm. ¿Qué presión debemos ejercer en
masha68 [24]

Answer:

2.61 atm

Ley de Boyle

Explanation:

P_1 = Presión inicial = 0.96 atm

P_2 = Presión final

V_1 = Volumen inicial = 95 mL

V_2 = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=\dfrac{0.96\times 95}{35}\\\Rightarrow P_1=2.61\ \text{atm}

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.

4 0
3 years ago
A constant friction force of 25 Nacts on a 65 kg skier for 20
Radda [10]

Answer:

The skier's change in velocity is 7.69 meters per second.

Explanation:

The Newton's second law tells force is equal to the change on the linear momentum of a body:

\sum\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}

If we approximate the differential \frac{d\overrightarrow{p}}{dt} to \frac{\Delta\overrightarrow{p}}{\Delta t}:

\sum\overrightarrow{F}=\frac{\Delta\overrightarrow{p}}{\Delta t}

Using that linear momentum is mass times velocity:

\sum\overrightarrow{F}=\frac{m\Delta\overrightarrow{v}}{\Delta t}

Solving for \Delta\overrightarrow{v}:

\Delta\overrightarrow{v}=\frac{\Delta t\sum\overrightarrow{F}}{m}=\frac{(20\,s)(25\,N)}{65\,kg}

\Delta\overrightarrow{v}=7.69\,\frac{m}{s}

3 0
3 years ago
Write a letter to a Friend congratulating her / him for her excellent result in annual examination. class 5 the​
gulaghasi [49]

Answer:

ok will do that

Explanation:

7 0
3 years ago
An unknown amount of a radioactive isotope with a half-life of 2.0 h was observed for 6.0 h. if the amount of the isotope remain
Grace [21]

The original amount of the radioactive isotope will be 8 grams.

<h3 /><h3>What is the half-life of radioisotopes?</h3>

The amount of time required for half of a radioisotope's nuclide to decay, or change into a different species, is known as its half-life. The conversions release either beta or alpha particles, and the response can be monitored by counting the particles released.

Given that an unknown amount of a radioactive isotope with a half-life of 2.0 h was observed for 6.0 h. if the amount of the isotope remaining after 6.0 h was 24 g.

The original amount will be calculated as below:-

( 2 / 6 ) = ( Original amount / 24 )

Original amount = 4 x 2

Original amount = 8 grams

Therefore, the original amount of the radioactive isotope will be 8 grams.

To know more about the half-life of radioisotopes follow

brainly.com/question/1783783

#SPJ4

5 0
2 years ago
A bomb, originally sitting at rest, explodes and during the
Archy [21]

Answer:

opposite

Explanation:

6 0
3 years ago
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