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3 years ago

In the diagram, DC is tangent to the circle, AC=12cm, and BD=2√34cm.Find AD.

Mathematics

1 answer:

Vesna [10]3 years ago

3 0

The answer is A 10 cm.

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I need help with this question!<br> Experts only please <br><br> Will mark brainliest

Naily [24]

3x + 2y(100)
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3 years ago

Kenny wrote the equation for a linear relationship shown below

Ilia_Sergeevich [38]

Y would equal -17! Good luck!

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3 years ago

Read 2 more answers

59 and/or 60. Determine if the triangles are similar. If they are similar, find the scale factor from ABC to JKL.

navik [9.2K]

9514 1404 393

Answer:

59) not similar

60)

Step-by-step explanation:

59) The ratios of the side lengths shown cannot be reduced. They are different, so the triangles are not similar.

7:8:12 ≠ 6:7:11

60) The side length ratios both reduce to 8:7:10, so the triangles are similar.

∆ABC ~ ∆JKL

The scale factor is LJ/CA = 25/20 = 5/4. (Multiplying ABC by 5/4 will give JKL.)

8 0

3 years ago

The total surface area of a cuboid is 600cm ^2 find LSA

Alona [7]

Answer:

Hope this help uh

Please make me brilliant

8 0

3 years ago

Which represents r in terms of A and S?

ladessa [460]

Answer:

$r=\frac{6\sqrt{10AS}}{S\sqrt{\pi }}$

Step-by-step explanation:

Given the formula;

$A=\frac{\pi r^2S}{360}$

We want to solve the given formula for r.

Multiply both sides by $\frac{360}{\pi S}$

$A\times \frac{360}{\pi S}=\frac{\pi r^2S}{360} \times \frac{360}{\pi S}$

$A\times \frac{360}{\pi S}=r^2$

Take square root of both sides

$r=\sqrt{\frac{360A}{\pi S}}$

$r=\frac{\sqrt{360A}}{\sqrt{\pi S}}$

$r=\frac{\sqrt{360A}}{\sqrt{\pi }\sqrt{S}}$

$r=\frac{\sqrt{360A}\times \sqrt{S}}{\sqrt{\pi }\sqrt{S} \times \sqrt{S}}$

$r=\frac{\sqrt{360AS}}{S\sqrt{\pi }}$

$r=\frac{6\sqrt{10AS}}{S\sqrt{\pi }}$

5 0

3 years ago