Answer:
(x^2 - 4)(x^2 - 3)
Step-by-step explanation:
Let y equal to x^2. We can rewrite the expression as:
y^2 - 7y + 12
Now, we have to look for numbers that have a product of 12 and a sum of -7. These numbers are -3 and -4. We can factor the equation:
(y - 4)(y - 3)
Now, we can substitute x^2 back in(we defined y as x^2 before):
(x^2 - 4)(x^2 - 3)
y-2 = 3(x+7) put it in y=mx+b form (slope intercept)
y-2 = 3(x+7) distribute 3
y-2 = 3x+21 add 2 to both sides
+2 +2
y = 3x + 23
so now the slope of that is 3 so the new equation has a slope of 3 because parallel slopes are equal.
my new line has a slope of 3 and point (4,2)
so we use point slope formula y-y1 = m(x-x1)
y-2 =3(x-4) put it in y=mx+b form (slope intercept)
y-2 = 3(x-4) distribute 3
y-2 = 3x -12 add 2 to both sides
+2 +2
y = 3x + 10 which is you line slope intercept with parallel slope and contains (4,2)
Answer:
no identity will escape! I know where you live
Answer:
I think it's y=15x+0
Step-by-step explanation:
y=mx+b
y=15x+0
I attached a picture from desmos.