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IceJOKER [234]
3 years ago
8

45% of 20 is what I need help and I need u to explain it please thank u

Mathematics
1 answer:
lora16 [44]3 years ago
5 0
45% of 20
20  times 0.45
= 9 
The answer is 9
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Please help n show work
notsponge [240]

x = time in minutes

y = distance remaining

Steve starts at home when the time is x = 0 minutes. The y value y = 40 pairs up with this x value. This is shown by the point (0,40) on the diagonal line, aka the y intercept. The y intercept is where the line crosses the y axis.

The y = 40 indicates that Steve has 40 miles remaining when he starts at home. In other words, the distance from home to work is 40 miles.

The x intercept is where the diagonal line crosses or touches the x axis. The x intercept is (45,0) which represents the idea that 45 minutes have passed by. The y = 0 means that he has 0 miles left go to. Steve has reached the office at this point.

-----------------------------------------------

Answers:

Steve's office is located 40 miles from home

It takes him 45 minutes to travel this distance

3 0
3 years ago
An asset is purchased on April 1st and has an annual depreciation amount of $3,600. Using the straight-line method of depreciati
Free_Kalibri [48]
From April to December =9 months

the depreciation expense
3,600×(9÷12)=2,700
5 0
3 years ago
Read 2 more answers
What is "three hundred nineteen thousandths" in decimal form
steposvetlana [31]

Answer:

319/1000= 0.319

Your welcome Brainliest plz

6 0
3 years ago
Amira is painting a rectangular banner 2 1/4 yards wide in the cafeteria. The banner will have a blue background. Amira has enou
elena55 [62]
Area of a rectangle:
A = w x h, where w is the width and h is the height.
w = 2.25 yd
A = 1.5 yd²
1.5 = 2.25 · h
h = 1.5 : 2.25 = 0.6667 = 2/3 yd
Answer:
The height of a banner is 2/3 yard.
4 0
3 years ago
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A rectangle and a square have the same area. a. The width of the rectangle is w inches. The length of the rectangle is 15 inches
harkovskaia [24]

9514 1404 393

Answer:

  a) w(4w-15)

  b) w²

  c) w(4w -15) = w²

  d) w = 5

  e) 5 by 5

Step-by-step explanation:

a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.

  A = w(4w -15)

__

b) If w is the side length, the area of the square is (also) the product of length and width:

  A = w²

__

c) Equating the expressions for area, we have ...

  w(4w -15) = w²

__

d) we can subtract the right side to get ...

  4w² -15w -w² = 0

  3w(w -5) = 0

This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.

The side length of the square is 5 units.

__

e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.

The rectangle and square have the same width and the same area, so the rectangle must be a square.

4 0
3 years ago
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