Answer:
260 cm
Step-by-step explanation:
Each 1/00 of a meter is 1 cm, so 65/100 meters is 65 cm. If that is the length of paper required for 1 kite, then 4 times that length will be required for 4 kites.
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The paper required for 4 kites is ...
(65 cm) × 4 = 260 cm
The correct answer to this problem is be because you have to multiply the 4 outside of the parentheses with the 4 inside of the parentheses which gives you 16X and then afterwards you have to do the same with the 6 with so since 4•6=24 you can automatically eliminate answer choice D and then you add up your 3x to your 16x which will be 19x so it would be B. 19x+24
Amu of unknown element = 40 - (20% * 40)
= 40 - 8
= 38 amu
therefore, the approximate weight of the unknown element is 38 amu.
hope this helps.