All categories

3 years ago

4 times what number gives you 24

Mathematics

2 answers:

VashaNatasha [74]3 years ago

8 0

6x4 = 24
Therefore, 24 is your answer.

uranmaximum [27]3 years ago

4 0

Your answer should be 6 × 4 =24

You might be interested in

Please help me asap!!

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Evaluate the square root of x^2 - 5x when x = 7. Round your answer to the nearest hundredth

Troyanec [42]

X^2-5x, given x=7,

(7)^2-5(7)=14

sqrt(14)=3.74

5 0

2 years ago

Read 2 more answers

Question: -2 - (-4)

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

Follow PEDMAS

$-2 - (-4)$

Follow rule : -(-a)= + a

$- 2 + 4 \\ = 2$

5 0

2 years ago

Read 2 more answers

In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz

Mekhanik [1.2K]

Answer:

We have 20 category Questions split into 5

Where we would assume that the 3rd question is simply 1/4 + 5/20 chance.

This is not a determiner as Robin is asked more questions.

So it is simply 1/4 and kept to factors that Robin will answer one of the 4 choices upon the 3rd question as 1/4 regardless of other questions being asked. Where Robins first answer would be the third question we subtract 4/5 = 16/20 - 5/20= 11/40. Which can only be rounded down to 2 decimal places 0.275

Step-by-step explanation:

7 0

3 years ago

Which expression should you simplify to find the 90% confidence interval,

Alex787 [66]

Answer:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is $\hat p=0.45$

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value is:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the true population proportion is interest is given by this formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing the values provided we got:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

8 0

2 years ago