Question

Not too sure about this one

Answer 1

Answer:

see explanation

Step-by-step explanation:

let y = f(x), then

y = 11x - 1

Interchange x and y and solve for y

x = 11y - 1 ( add 1 to both sides )

x + 1 = 11y ( divide both sides by 11 )

y = $\frac{x+1}{11}$, hence

$f^{-1}$(x) = $\frac{x+1}{11}$