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Anuta_ua [19.1K]
4 years ago
6

Not too sure about this one

Mathematics
1 answer:
elena-s [515]4 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

let y = f(x), then

y = 11x - 1

Interchange x and y and solve for y

x = 11y - 1 ( add 1 to both sides )

x + 1 = 11y ( divide both sides by 11 )

y = \frac{x+1}{11}, hence

f^{-1}(x) = \frac{x+1}{11}

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Quick algebra 1 question for 10 points!
Maslowich

The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

<h3>What is the range of a quadratic equation?</h3>

In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.

x = - 9

y = (2 / 3) · (- 9)² - 6

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x = - 6

y = (2 / 3) · (- 6)² - 6

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x = - 3

y = (2 / 3) · (- 3)² - 6

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y = 0

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y = (2 / 3) · 6² - 6

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The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

To learn more on functions: brainly.com/question/12431044

#SPJ1

7 0
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