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3 years ago

Please help me!Choose the correct solution and graph for the inequality. 4-6

Mathematics

2 answers:

natka813 [3]3 years ago

6 0

The answer is x |< -9
Because
X-3\< -12
X\< -12+3
X\< -9
X\< -9 is the answer

Ahat [919]3 years ago

3 0

1. x $\leq$ -9

2. x $\leq$ 5

3. y $\leq$ -12

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Find the measure of ∠C if ∠A = 3 2 x + 20 ∠B = 7 2 x + 20 ∠C = 5 2 x + 40 ∠D = 3 2 x + 10 A) 65° B) 76° C) 95° D) 115°

Rudiy27

The sum of the angles of a quadrilateral is 360°.
$\left(\dfrac{3}{2}x+20\right)+\left(\dfrac{7}{2}x+20\right)+\left(\dfrac{5}{2}x+40\right)+\left(\dfrac{3}{2}x+10\right)=360\\\\9x+90=360\\\\x=\dfrac{270}{9}=30$

Given that x=30, the measure of ∠C is
∠C = (5/2)×30 +40 = 115

The appropriate choice is ...
D) 115°

5 0

3 years ago

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AYUDAAAAAAA!!!!!

krok68 [10]

Answer:

Forma exacta:

x= −37/30

Forma decimal:

x=−1.23

Forma numérica mixta:

x=−17/30

8 0

3 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

Math answer plz need help with this plz answer

Neporo4naja [7]

Answer:

176.625 sq.ft, 4.8 sq.ft

Step-by-step explanation:

Area of circle=πr^2 or πd^2/4
11. Given,
d=15 ft
Now,
Area=πd^2/4
3.14*15^2/4
176.625 ft^2
Therefore, the area approximation is 176.6 sq.ft
12.
Given,
d=3.5 ft
Now,
Area= πd^2/8
3.14*3.5^2/8
4.8 sq.ft
I got the answer by dividing the area of circle by 2 as semicircle is half of circle.

6 0

2 years ago

29/2 written as a mixed number?

Andru [333]

Answer:

14 $\frac{1}{2}$

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers