The function that has a range of y<3 is y=-(2)* + 3
Answer: Option(c)
<u>Step-by-step explanation:</u>
Solution:
Lets shall evaluate the options given in the question
In Option 1; y=3(2) that is

So the value of y>3 and thus option 1 fails
In option 2; y=2(3)*
This expression indicates that the power of 3 all result in positive values and sometimes zero such that for
and for values other than one y will be greater than 3. so option 2 fails.
In option 4; y=2x(-3)
On solving we get 
Though it is less than 3 but it has an negative value. So option 4 fails.
In option 3; y=-(2)* + 3
This option indicates for all power values of -2 the y value will be less than 3 such that
For power value 0 we get

y=0+3=3
And for the power value 1 we get

y=-2+3=1
So in the both the occasion the value of y<3 than and it is not an negative value and thus option 3 satisfy the functional range y<3.
Result:
Thus the function that has a range of y<3 is y=-(2)* + 3
Answer:
Yes, he is correct because 35 percent of 20 is 7.
Step-by-step explanation:
8 / 4 = 2 ;
z^8 / z^4 = z^4 ;
then, 8z^4 / 4z^4 = 2z^4 ;
finally, ( 8z^4 / 4z^4 )^ -4 = ( 2z^4 )^ - 4 = 1 / ( 2z^4 )^4 = 1 / [ 2^4 * ( z^4 )^ 4 ] = 1 / ( 16 * z^16 )
Answer:
Relation between V and c is represented as:

When c is halved, V becomes
of its initial value.
Step-by-step explanation:
Height of cylinder = Radius of cylinder = c
Volume of cylinder = V
As per formula:

Where
is the radius of cylinder and
is the height of cylinder
Putting 

The values of c is halved:
Using equation (1), New volume:

By equation (1), putting 

So, when c is halved, V becomes
of its initial value.