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lara [203]
2 years ago
5

How much is 1/9 of 3/8 (in lowest terms)? A)4/17 B)03/17 C)1/36 D)1/24

Mathematics
1 answer:
mojhsa [17]2 years ago
8 0

Answer:

1/24

Step-by-step explanation:

multiply 1/9 and 3/8. The product of the two factors is 3/ 72. Seeing the two factors on the other hand, we can cancel out 3. Hence the final answer to this problem in lowest terms becomes 1/24.

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One number is 4 times number another. Their sum is 35. Find the number
jonny [76]

Answer:

7

Step-by-step explanation:

n+4n=35

5n=35

5n/5=35/5

n=7

3 0
3 years ago
What is the value of the expression 10 − ( fraction 1 over 2 )4 ⋅ 48? (1 point)
OlgaM077 [116]

Answer:

Just want to ask if it is 10 - 1/2 × 4 × 48 right? If the expression is this then the answer is -86.

Hope this helps, thank :) !!

6 0
3 years ago
Find the perimeter of the figure <br> 13.5 ft<br> 9 ft<br> 12.5 ft
saveliy_v [14]

Answer:

Add all the values up and then divide by 2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which of the following are valid names for the given polygon
barxatty [35]
B,C and D are correct because all of those choices include letters which are arranged in order from left of right.
5 0
3 years ago
The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged
Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

  • X is the left atrial diameter value we are looking for its z-score
  • M is the mean left atrial diameter of healthy children (26.7 mm)
  • s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

5 0
3 years ago
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