Ask question

Ask question

All categories

3 years ago

11

Which equation would you use to find x?

1 answer:

Nitella [24]3 years ago

8 0

You would use B to find X

You might be interested in

What is the factors of p(x)=x^2+7√2x+4<br>PLEAE HELP!

valentina_108 [34]

Answer:

aasha here it is.

Step-by-step explanation:

3x−1)(2x+3)

6x2+7x−3

=6x2+9x−2x−3

=3x(2x+3)−1(2x+3)

=(2x+3)(3x−1)

and hiii

5 0

3 years ago

Evaluate the summation of 2n+5 from n=1 to 12<br><br> 29<br> 36<br> 216<br> 432

rewona [7]

$\bf \sum\limits_{n=1}^{12}\ 2n+5\implies \sum\limits_{n=1}^{12}\ 2n+\sum\limits_{n=1}^{12}\ 5\implies 2\sum\limits_{n=1}^{12}\ n+\sum\limits_{n=1}^{12}\ 5
\\\\\\
2\cdot \cfrac{12(12+1)}{2}+(12\cdot 5)\implies 156+60\implies 216$

3 0

3 years ago

lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

zaharov [31]

Answer with Step-by-step explanation:

Given

$f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1$

6 0

3 years ago

Please find the slope and the equation.<br><br>and step by step explanation PLEASE.

Lisa [10]

Answers:

slope = 1
equation is y = x-4

============================================

Explanation:

Two points on this diagonal line are (0,-4) and (1,-3)

Let's apply the slope formula to get the following

m = (y2-y1)/(x2-x1)

m = (-3-(-4))/(1-0)

m = (-3+4)/(1-0)

m = 1/1

m = 1

The slope is 1. We can think of it as 1/1 to indicate "go up 1, and over to the right 1". In other words, slope = rise/run = 1/1.

----------

Note how the graph crosses the y axis at -4, so this is the y intercept.

Since the y intercept is -4, this means b = -4

So with m = 1 and b = -4, we go from y = mx+b to y = 1x+(-4) which simplifies to y = x-4

3 0

3 years ago

6. Find the values for each of the following: a. 3 times 5 in Z1o b. 3 times 5 in Zs c. 3 times 5 in Z3 e. 5 3 in Z1o

Anettt [7]

Answer: The calculations are done below.

Step-by-step explanation: We are given to find the values for each of the following :

(A) 3 times 5 in $\mathbb{Z}_{10}.$

We know that

$\mathbb{Z}_{10}=\{0,1,2,3,4,5,6,7,8,9\}(\textup{mod}10).$

Therefore, we get

$3\times5=15(\textup{mod}10)=5.$

(B) 3 times 5 in $\mathbb{Z}_{5}.$

We know that

$\mathbb{Z}_{5}=\{0,1,2,3,4\}(\textup{mod}5).$

Therefore, we get

$3\times5=15(\textup{mod}5)=0.$

(C) 3 times 5 in $\mathbb{Z}_{3}.$

We know that

$\mathbb{Z}_{3}=\{0,1,2\}(\textup{mod}3).$

Therefore, we get

$3\times5=15(\textup{mod}3)=0.$

(D) 5 times 3 in $\mathbb{Z}_{10}.$

We know that

$\mathbb{Z}_{10}=\{0,1,2,3,4,5,6,7,8,9\}(\textup{mod}10).$

Therefore, we get

$5\times3=15(\textup{mod}10)=5.$

Thus, the required values are evaluated.

8 0

3 years ago