a. There are four 5s that can be drawn, and 
ways of drawing any three of them. There are 
ways of drawing any three cards from the deck. So the probability of drawing three 5s is
In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of 
of getting drawn.
b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability 
of being drawn.
c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of 
.
- - -
Note: 
is the binomial coefficient,
Answer:
-343p^3
Step-by-step explanation:
This is the answer because -7x-7x-7 would be -343 and you MUST keep the negative sign. The p x pxp would be p^3
Multiply the numbers:
-343p^3 would be your answer
Hope this helps!! :D
Let
x = loaves of bread
y = batches of muffins
You must make a system of two equations with two unknowns that describe the problem
3.5x + 2.5y = 17 --- (1)
0.75x + 0.75y = 4.5 --- (2)
Resolving we have
x = 6-y (from (2))
replacing in (1)
3.5 (6-y) + 2.5y = 17
21 - 3.5y + 2.5y = 17
y = 21-17 = 4
Then substituting in (2)
x = 6-y = 6-4 = 2
Answer
Helena could bake:
2 loaves of bread
4 batches of muffins
4p(x-4)-5
That is my answer I hope I’m right have a merry Christmas
