12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
Answer:
y=30x^2+36x+48 OR f(x)=30x^2+36x+48
This is an exponential function/exponential graph. Hope I helped!
Step-by-step explanation:
Given: y=2(3x+6)(5x-4)
Use the distributive property!: y=(6x+12)(5x-4)
Use the distributive property!: y=(5x(6x+12)-4(6x+12))
Use the distributive property!: y=(30x^2+60x)-(24x+48)
Remove parenthesis: y=30x^2+60x-24x+48y=30x^2+36x+48 OR f(x)=30x^2+36x+48
This is an exponential function/exponential graph. Hope I helped!
-9x-5y=12
C) (2, -6) -18+30=12
Answer:
The height is 7 cm
Step-by-step explanation:
210 × 2 = 420
12 × 5 = 60
420 ÷ 60 = 7
First divide by 8:_
38 / 8 = 4 remainder 6
so its 46
