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3 years ago

5

What is they nearest liter to 103.468

2 answers:

4vir4ik [10]3 years ago

6 0

Answer:

In this question, you are asked to do rounding.

The number will be rounded up if 1 digit below them is having value 5 or more. The number will be rounded down instead if 1 digit below it was 4 or less. In this case, you need to round up to nearest liters which mean the nearest one. The number is 103.468.

One digit below one will be the 0.4. Since the value is 4, which was lower than 5, then the number is rounded down. So the answer would be 103.

Found on brainly.com/question/1025081

Step-by-step explanation:

Volgvan3 years ago

4 0

Answer:

Step-by-step explanation:

it rounds to 103

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3 years ago

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Answer:

Coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q $(x_2,y_2)$

We will use the formula of midpoint: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We are given midpoint K and $x_1,y_1$ the coordinates of P we need to find $x_2,y_2$ the coordinates of Q.

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\$

Now, we can write

$-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16$

So, we get coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

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