<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
.5(20x-50y+36)-.25(-100x+40y-12)
10x-25y+18+25x-10y+3
35x-25y+18-10y+3
35x-35y+18+3
35x-35y+21
Answer:
Step-by-step explanation:
Expand:
Add 27 to both sides:
Add 12x to both sides:
Divide both sides by 4:
Answer:
1. y² - 3x - 18
2. 4x² - 33x + 35
3. 12x² - 11x + 2
Step-by-step explanation:
All we do with these questions are expanding the factored binomials. Use FOIL:
1. y² + 3y - 6y - 18
y² - 3y - 18
2. 4x² - 28x - 5x + 35
4x² - 33x + 35
3. 12x² - 3x - 8x + 2
12x² - 11x + 2
Hey there!
64 + 8 = 72
so x = 8
Hope this helps
Have a great day (:
