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stira [4]
3 years ago
13

What is the distance between the two points M(8, -5) and N(-13, 4)?

Mathematics
2 answers:
Goryan [66]3 years ago
7 0
The distance between M(8, -5) and N(-13, 4) is 22.8473.

WHAT FORMULA SHOULD I USE?:
d(A, B) =  \sqrt{(xB-xA)^2 + (yB-yA)^2}
xeze [42]3 years ago
4 0
The distance formula is sqare root (x-x)^2+(y-y)^2 and then you will plug in 

sqrt(8+13)^2+(4+5)^2
 
plug that in to your calculator and that will be your answer what ever you get
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3 years ago
SIMPLIFY and SHOW WORK THANKS 3∙[ 9 – 2∙ (7 – 8)]
Zepler [3.9K]

Answer:

33

Step-by-step explanation:

3∙[ 9 – 2∙ (7 – 8)]

PEMDAS,

Parentheses, start from the inside out

3∙[ 9 – 2∙ (-1)]

3∙[ 9 +2]

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8 0
3 years ago
Jill buys a t-shirt for $12.79 and a pair of socks for $6.75 at the mall. How much did she spend?
Pie

Answer:

$12.79 + $6.75 = $19.54

Step-by-step explanation:

3 0
2 years ago
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sertanlavr [38]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
2 years ago
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